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Difference between revisions of "Differentiation Rules"

(→‎Derivatives of Trig Functions)
 
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If <math>y(x) = u(x)+v(x)</math> then <math>\frac{dy}{dx} = \frac{du}{dx} + \frac{dv}{dx}</math>.
 
If <math>y(x) = u(x)+v(x)</math> then <math>\frac{dy}{dx} = \frac{du}{dx} + \frac{dv}{dx}</math>.
  
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'''Product Rule:'''
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[[Product Rule]]:
 
If <math>y(x) = u(x) \cdot v(x)</math> then <math>\frac{dy}{dx} = u(x)\frac{dv}{dx} + v(x)\frac{du}{dx}</math>.
 
If <math>y(x) = u(x) \cdot v(x)</math> then <math>\frac{dy}{dx} = u(x)\frac{dv}{dx} + v(x)\frac{du}{dx}</math>.
  
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'''Quotient Rule:'''
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[[Quotient Rule]]:
 
If <math>y(x) = \frac{u(x)}{v(x)}</math> then <math>\frac{dy}{dx} = \frac{v(x)\frac{du}{dx} - u(x)\frac{dv}{dx}}{(v(x))^2}</math>.
 
If <math>y(x) = \frac{u(x)}{v(x)}</math> then <math>\frac{dy}{dx} = \frac{v(x)\frac{du}{dx} - u(x)\frac{dv}{dx}}{(v(x))^2}</math>.
  
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'''Chain Rule:'''
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[[Chain Rule]]:
 
If <math>y(x) = u(v(x))</math> then <math>\frac{dy}{dx} = \frac{du}{dv}\cdot \frac{dv}{dx}</math>.
 
If <math>y(x) = u(v(x))</math> then <math>\frac{dy}{dx} = \frac{du}{dv}\cdot \frac{dv}{dx}</math>.
  
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'''Derivative of Sine'''
 
'''Derivative of Sine'''
 
If <math>y(x) = \sin x</math>, then <math>\frac{dy}{dx} = \cos x</math>.
 
If <math>y(x) = \sin x</math>, then <math>\frac{dy}{dx} = \cos x</math>.
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 +
'''Derivative of Cosine'''
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If <math>y(x) = \cos x</math>, then <math>\frac{dy}{dx} = -\sin x</math>.
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 +
'''Derivative of Tangent'''
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If <math>y(x) = \tan x</math>, then <math>\frac{dy}{dx} = \sec^2 x</math>. Note that this follows from the Quotient Rule.

Latest revision as of 00:53, 26 March 2018

Differentiation rules are rules (actually, theorems) used to compute the derivative of a function in calculus. In what follows, all functions are assumed to be differentiable.

Basic Rules

Derivative of a Constant: If $y(x)=c$ is a constant function then $\frac{dy}{dx} = 0$.

Sum Rule: If $y(x) = u(x)+v(x)$ then $\frac{dy}{dx} = \frac{du}{dx} + \frac{dv}{dx}$.

Product Rule: If $y(x) = u(x) \cdot v(x)$ then $\frac{dy}{dx} = u(x)\frac{dv}{dx} + v(x)\frac{du}{dx}$.

Quotient Rule: If $y(x) = \frac{u(x)}{v(x)}$ then $\frac{dy}{dx} = \frac{v(x)\frac{du}{dx} - u(x)\frac{dv}{dx}}{(v(x))^2}$.

Chain Rule: If $y(x) = u(v(x))$ then $\frac{dy}{dx} = \frac{du}{dv}\cdot \frac{dv}{dx}$.

Power Rule: If $y(x) = (u(x))^n$ then $\frac{dy}{dx} = n(u(x))^{n-1} \cdot \frac{du}{dx}$. For integer $n$ this is just a consequence of the product and quotient rules and induction, but it can also be proven for all real numbers $n$, e.g. by using the extended Binomial Theorem.

Derivatives of Trig Functions

Derivative of Sine If $y(x) = \sin x$, then $\frac{dy}{dx} = \cos x$.

Derivative of Cosine If $y(x) = \cos x$, then $\frac{dy}{dx} = -\sin x$.

Derivative of Tangent If $y(x) = \tan x$, then $\frac{dy}{dx} = \sec^2 x$. Note that this follows from the Quotient Rule.

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