https://artofproblemsolving.com/wiki/index.php?title=Division_Theorem&feed=atom&action=historyDivision Theorem - Revision history2024-03-28T08:33:46ZRevision history for this page on the wikiMediaWiki 1.31.1https://artofproblemsolving.com/wiki/index.php?title=Division_Theorem&diff=42967&oldid=prevProgramingMaster: Fixed spelling error: "iff" to "if"2011-11-10T20:45:57Z<p>Fixed spelling error: "iff" to "if"</p>
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<td colspan="2" style="background-color: #fff; color: #222; text-align: center;">Revision as of 20:45, 10 November 2011</td>
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<tr><td class='diff-marker'>−</td><td style="color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #ffe49c; vertical-align: top; white-space: pre-wrap;"><div>For any positive integers <math> a </math> and <math> b </math>, there exist unique integers <math> q </math> and <math> r </math> such that <math> b = qa + r </math> and <math> 0 \le r < a </math>, with <math> r = 0 </math> <del class="diffchange diffchange-inline">iff </del><math> a | b. </math></div></td><td class='diff-marker'>+</td><td style="color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;"><div>For any positive integers <math> a </math> and <math> b </math>, there exist unique integers <math> q </math> and <math> r </math> such that <math> b = qa + r </math> and <math> 0 \le r < a </math>, with <math> r = 0 </math> <ins class="diffchange diffchange-inline">if </ins><math> a | b. </math></div></td></tr>
</table>ProgramingMasterhttps://artofproblemsolving.com/wiki/index.php?title=Division_Theorem&diff=40216&oldid=prevJmclaus at 00:34, 5 July 20112011-07-05T00:34:35Z<p></p>
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<td colspan="2" style="background-color: #fff; color: #222; text-align: center;">Revision as of 00:34, 5 July 2011</td>
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</table>Jmclaushttps://artofproblemsolving.com/wiki/index.php?title=Division_Theorem&diff=26650&oldid=prevLatenightworker13: New page: For any positive integer a and integer b, there exist unique integers q and r such that b = qa + r and 0 <= r < a, with r = 0 iff a | b.2008-06-18T11:31:30Z<p>New page: For any positive integer a and integer b, there exist unique integers q and r such that b = qa + r and 0 <= r < a, with r = 0 iff a | b.</p>
<p><b>New page</b></p><div>For any positive integer a and integer b, there exist unique integers q and r such that b = qa + r and 0 <= r < a, with r = 0 iff a | b.</div>Latenightworker13