Difference between revisions of "Euclid's proof of the infinitude of primes"

Revision as of 18:21, 15 January 2007

This is proved by contradiction. Suppose there is a finite number of primes and let them be $p_1,p_2,p_3,...,p_n$ . Let $x=p_1p_2p_3\cdots p_n$ . Then we have $x+1=p_1p_2p_3\cdots p_n+1$ . When divided by any of the primes $p_1,p_2,p_3,...,p_n$ , $x+1$ leaves a remainder of 1 implying that either $x+1$ is prime or that it has some other prime factors not in the set $\{ p_1,p_2,p_3,...,p_n\}$ . In any case we have it so that $\{ p_1,p_2,p_3,...,p_n\}$ does not contain all prime numbers. Contradiction!

Page

Toolbox

Search

Difference between revisions of "Euclid's proof of the infinitude of primes"

Revision as of 18:21, 15 January 2007

Revision as of 23:04, 16 December 2006 (view source) Cosinator (talk \| contribs)	Revision as of 18:21, 15 January 2007 (view source) JBL (talk \| contribs) m (Euclid's proof on the infitude of primes moved to Euclid's proof of the infitude of primes) Newer edit →
(No difference)