Difference between revisions of "Euler's Polyhedral Formula"

(stub)
m (Added icosahedron to table.)
 
(9 intermediate revisions by 7 users not shown)
Line 1: Line 1:
 
Let <math>P</math> be any [[convex]] [[polyhedron]], and let <math>V</math>, <math>E</math> and <math>F</math> denote the number of [[vertex|vertices]], [[edge]]s, and [[face]]s, respectively. Then <math>V-E+F=2</math>.
 
Let <math>P</math> be any [[convex]] [[polyhedron]], and let <math>V</math>, <math>E</math> and <math>F</math> denote the number of [[vertex|vertices]], [[edge]]s, and [[face]]s, respectively. Then <math>V-E+F=2</math>.
 +
 +
==Observe!==
 +
Apply Euler's Polyhedral Formula on the following polyhedra:
 +
 +
<math> \begin{tabular}{|c|c|c|c|}\hline Shape & Vertices & Edges & Faces\\ \hline Tetrahedron &4  &6 & 4 \\ \hline Cube/Hexahedron & 8 & 12 & 6\\ \hline Octahedron & 6 & 12 & 8\\ \hline Dodecahedron & 20 & 30 & 12\\ \hline Icosahedron & 12 & 30 & 20\\ \hline \end{tabular} </math>
 +
 +
==Problem==
 +
A convex polyhedron has for its faces 12 squares, 8 regular hexagons, and 6 regular octagons. At each vertex of the polyhedron one square, one hexagon, and one octagon meet. How many segments joining vertices of the polyhedron lie in the interior of the polyhedron rather than along an edge or a face? (1988 AIME #10)
  
 
== See Also ==
 
== See Also ==
Line 5: Line 13:
 
* [[Euler characteristic]]
 
* [[Euler characteristic]]
  
 +
{{stub}}
  
{{stub}}
+
[[Category:Theorems]]
 +
[[Category:Geometry]]

Latest revision as of 14:15, 6 March 2022

Let $P$ be any convex polyhedron, and let $V$, $E$ and $F$ denote the number of vertices, edges, and faces, respectively. Then $V-E+F=2$.

Observe!

Apply Euler's Polyhedral Formula on the following polyhedra:

$\begin{tabular}{|c|c|c|c|}\hline Shape & Vertices & Edges & Faces\\ \hline Tetrahedron &4  &6 & 4 \\ \hline Cube/Hexahedron & 8 & 12 & 6\\ \hline Octahedron & 6 & 12 & 8\\ \hline Dodecahedron & 20 & 30 & 12\\ \hline Icosahedron & 12 & 30 & 20\\ \hline \end{tabular}$

Problem

A convex polyhedron has for its faces 12 squares, 8 regular hexagons, and 6 regular octagons. At each vertex of the polyhedron one square, one hexagon, and one octagon meet. How many segments joining vertices of the polyhedron lie in the interior of the polyhedron rather than along an edge or a face? (1988 AIME #10)

See Also

This article is a stub. Help us out by expanding it.