Difference between revisions of "Euler's Totient Theorem Problem 1 Solution"
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==Solution== | ==Solution== | ||
| − | This is a direct application of Euler's Totient Theorem. Since <math> \phi(100)=40 </math>, this reduces to <math> 7^1-3^1\equiv \boxed{04}\pmod{100} </math>. -BorealBear | + | This is a direct application of [[Euler's Totient Theorem]]. Since <math> \phi(100)=40 </math>, this reduces to <math> 7^1-3^1\equiv \boxed{04}\pmod{100} </math>. -BorealBear |
Latest revision as of 17:33, 21 March 2023
Problem
(BorealBear) Find the last two digits of 
.
Solution
This is a direct application of Euler's Totient Theorem. Since 
, this reduces to 
. -BorealBear
