Difference between revisions of "Formulas relating the number of lines, sections, and intersection points"

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<cmath>\text{Some formulas relating the number of intersections, lines, and sections in a plane.}</cmath>
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\text{Some formulas relating the number of intersections, lines, and sections in a plane.}
<math></math>\text{1) The maximum number of intersection points of n lines is <math>\frac{n(n-1)}{2}</math>.}<cmath>
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\text{1) The maximum number of intersection points of n lines is <math>\frac{n(n-1)}{2}</math>.}
 
Proof: Each line intersects all the other lines to create the maximum number of intersections. The first line intersects n-1 lines, the second one has n-2
 
Proof: Each line intersects all the other lines to create the maximum number of intersections. The first line intersects n-1 lines, the second one has n-2
 
new intersection points, and so on.
 
new intersection points, and so on.
</cmath>\text{2) The maximum number of planar sections (assuming the plane is bound at some point) created by n lines is \frac{n^2+n+2}{2}}<cmath>
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\text{2) The maximum number of planar sections (assuming the plane is bound at some point) created by n lines is \frac{n^2+n+2}{2}}
 
Proof: Before there are any lines, there is one section. The first line passes through one section, splitting it in two. The second line passes through  
 
Proof: Before there are any lines, there is one section. The first line passes through one section, splitting it in two. The second line passes through  
 
two sections, splitting it into a total of four sections. The third line passes through a maximum of three existing sections, adding three new sections to the  
 
two sections, splitting it into a total of four sections. The third line passes through a maximum of three existing sections, adding three new sections to the  
 
plane. (someone turn this into a formal proof with induction please)
 
plane. (someone turn this into a formal proof with induction please)
</cmath>\text{3)The number of lines + number of intersection points = number of sections -1 assuming that no three lines intersect at one point.}<cmath>
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\text{3)The number of lines + number of intersection points = number of sections -1 assuming that no three lines intersect at one point.}
 
The proof can be made by bashing the equation with the previous formulas
 
The proof can be made by bashing the equation with the previous formulas
</cmath>\text{4) The number of curved lines (enclosed circles)+ number of lines+ number of intersection points -1= number of sections created, provided that no three curved or straight lines intersect at the same point.}<math></math>
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\text{4) The number of curved lines (enclosed circles)+ number of lines+ number of intersection points -1= number of sections created, provided that no three curved or straight lines intersect at the same point.}
 
Proof: Almost the same, note however that two curved lines and intersect at two points, same for one curved and one straight line.
 
Proof: Almost the same, note however that two curved lines and intersect at two points, same for one curved and one straight line.

Revision as of 17:17, 4 June 2013

\text{Some formulas relating the number of intersections, lines, and sections in a plane.} \text{1) The maximum number of intersection points of n lines is $\frac{n(n-1)}{2}$.} Proof: Each line intersects all the other lines to create the maximum number of intersections. The first line intersects n-1 lines, the second one has n-2 new intersection points, and so on. \text{2) The maximum number of planar sections (assuming the plane is bound at some point) created by n lines is \frac{n^2+n+2}{2}} Proof: Before there are any lines, there is one section. The first line passes through one section, splitting it in two. The second line passes through two sections, splitting it into a total of four sections. The third line passes through a maximum of three existing sections, adding three new sections to the plane. (someone turn this into a formal proof with induction please) \text{3)The number of lines + number of intersection points = number of sections -1 assuming that no three lines intersect at one point.} The proof can be made by bashing the equation with the previous formulas \text{4) The number of curved lines (enclosed circles)+ number of lines+ number of intersection points -1= number of sections created, provided that no three curved or straight lines intersect at the same point.} Proof: Almost the same, note however that two curved lines and intersect at two points, same for one curved and one straight line.