Difference between revisions of "Fundamental Theorem of Sato"

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Proof:
 
Proof:
  
Method 1: Proof by Contradiciton
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Method 1: Proof by Contradiction
  
 
Assume, for contradiction, that Sato is not amazing.
 
Assume, for contradiction, that Sato is not amazing.
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Method 3: Proof by Pigeonhole
 
Method 3: Proof by Pigeonhole
  
There is only one Sato. By Pigeonhole, either Sato is amazing or he isn't. Fortunately, Sato cannot fit in a pigeonhole; hence, Sato is amazing. (Proved)
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There is only one Sato. By Pigeonhole, either Sato is amazing or he isn't (in this case, Sato goes in the unamazing pigeonhole). Fortunately, Sato cannot fit in a pigeonhole; hence, Sato is amazing. (Proved)
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Method 4: Proof by Gmass
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Gmass is Sato in cat form. Since Gmass is amazing, and since if <math>a=b</math> and <math>b=c</math>, <math>a=c</math>, Sato is amazing.
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Learn about Sato:
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https://artofproblemsolving.com/wiki/index.php/Naoki_Sato
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Back to Main Page:
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https://artofproblemsolving.com/wiki/index.php/Main_Page
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Revision as of 14:50, 28 August 2019

The Fundamental Theorem of Sato states the following:

Sato is amazing.

Proof:

Method 1: Proof by Contradiction

Assume, for contradiction, that Sato is not amazing.

This is absurd. Therefore, Sato is amazing. (Proved)

Method 2: Proof by Authority

Whatever AoPS says is correct, and AoPS says that Mr. Sato is amazing. Thus, Mr. Sato is amazing. (Proved)

Method 3: Proof by Pigeonhole

There is only one Sato. By Pigeonhole, either Sato is amazing or he isn't (in this case, Sato goes in the unamazing pigeonhole). Fortunately, Sato cannot fit in a pigeonhole; hence, Sato is amazing. (Proved)

Method 4: Proof by Gmass

Gmass is Sato in cat form. Since Gmass is amazing, and since if $a=b$ and $b=c$, $a=c$, Sato is amazing.



Learn about Sato: https://artofproblemsolving.com/wiki/index.php/Naoki_Sato


Back to Main Page: https://artofproblemsolving.com/wiki/index.php/Main_Page