Difference between revisions of "Fundamental Theorem of Sato"

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There is only one Sato. By Pigeonhole, either Sato is amazing or he isn't (in this case, Sato goes in the unamazing pigeonhole). Fortunately, Sato cannot fit in a pigeonhole; hence, Sato is amazing. (Proved)
 
There is only one Sato. By Pigeonhole, either Sato is amazing or he isn't (in this case, Sato goes in the unamazing pigeonhole). Fortunately, Sato cannot fit in a pigeonhole; hence, Sato is amazing. (Proved)
 
Method 4: Proof by Gmass
 
 
Gmass is Ssto in cat form. Since Gmass is amazing, and since if <math>a=b</math> and <math>b=c</math>, <math>a=c</math>, Sato is amazing.
 
 
 
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Learn about Sato:
 
https://artofproblemsolving.com/wiki/index.php/Naoki_Sato
 
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Back to Main Page:
 
https://artofproblemsolving.com/wiki/index.php/Main_Page
 

Revision as of 20:44, 29 January 2023

The Fundamental Theorem of Sato states the following:

Sato is amazing.

Proof:

Method 1: Proof by Contradiction

Assume, for contradiction, that Sato is not amazing.

This is absurd. Therefore, Sato is amazing. (Proved)

Method 2: Proof by Authority

Whatever AoPS says is correct, and AoPS says that Mr. Sato is amazing. Thus, Mr. Sato is amazing. (Proved)

Method 3: Proof by Pigeonhole

There is only one Sato. By Pigeonhole, either Sato is amazing or he isn't (in this case, Sato goes in the unamazing pigeonhole). Fortunately, Sato cannot fit in a pigeonhole; hence, Sato is amazing. (Proved)