Gauss Grade 7 Year 2011 Problem 1

Revision as of 14:29, 5 July 2011 by Ahaanomegas (talk | contribs) (Created page with "=== Problem === The value of <math> 5 + 4 - 3 + 2 - 1 </math> is <cmath> \textbf {(A) 0} \ \ \ \textbf {(B) 5} \ \ \ \textbf {(C) 3} \ \ \ \textbf {(D) 3} \ \ \ \textbf {(E) 7}...")
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Problem

The value of $5 + 4 - 3 + 2 - 1$ is \[\textbf {(A) 0} \ \ \ \textbf {(B) 5} \ \ \ \textbf {(C) 3} \ \ \ \textbf {(D) 3} \ \ \ \textbf {(E) 7}\]

Solution

$5 + 4 - 3 + 2 - 1 = 9 - 3 + 2 - 1 = 6 + 1 = \boxed {\textbf {(E) 7}}$