Difference between revisions of "Jadhav Division Axiom"

(Created page with "'''Jadhav Division Axiom''', gives a way to '''correctly predict''' the number of digits before decimal point in an incomplete or improper, division process left with remainde...")
 
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In an incomplete division process if the dividend is '''lesser then''' Divisor into product of 10 raise to a '''power "k"''', and '''bigger then''' divisor into product of 10 with '''power "k-1"''' then there will be k number of terms before decimal point in an divisional process.
 
In an incomplete division process if the dividend is '''lesser then''' Divisor into product of 10 raise to a '''power "k"''', and '''bigger then''' divisor into product of 10 with '''power "k-1"''' then there will be k number of terms before decimal point in an divisional process.
  
==== <math>d \times 10^k-1<n < d \times 10^k  </math>  ====
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==== <math>d \times 10^{k-1}<n < d \times 10^k  </math>  ====
 
'''Number of digits before decimal point is k''' (here d represents divisor and n represents dividend)
 
'''Number of digits before decimal point is k''' (here d represents divisor and n represents dividend)
  
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== Other Discoveries by Jyotiraditya Jadhav ==
 
== Other Discoveries by Jyotiraditya Jadhav ==
  
* '''[[Jadhav theorem|Jadhav theorem]]'''
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* '''[[Jadhav Theorem|Jadhav Theorem]]'''
 
* '''[[Jadhav Triads]]'''  
 
* '''[[Jadhav Triads]]'''  
 
* '''[[Zeta]]'''
 
* '''[[Zeta]]'''
 
* '''[[Jadhav Isosceles Formula]]'''
 
* '''[[Jadhav Isosceles Formula]]'''

Latest revision as of 08:04, 12 July 2021

Jadhav Division Axiom, gives a way to correctly predict the number of digits before decimal point in an incomplete or improper, division process left with remainder zero and a Quotient with decimal part, given by Jyotiraditya Jadhav

Statement

In an incomplete division process if the dividend is lesser then Divisor into product of 10 raise to a power "k", and bigger then divisor into product of 10 with power "k-1" then there will be k number of terms before decimal point in an divisional process.

$d \times 10^{k-1}<n < d \times 10^k$

Number of digits before decimal point is k (here d represents divisor and n represents dividend)

Practical Observations

22/7 = 3.14

here { 7 X 10 ^(1-1) < 22 < 7 X 10^1 } , so number of digits before decimal point is 1

100/ 6 = 16.6

here {6 X 10^(2-1)<100<6 X 10^2 }, so number of digits before decimal point is 2

Uses

  • All type of division processes
  • Can be used to correctly predict the nature of the answer for long division processes.
  • Can be used to determine the sin and cosine functions of extreme angles

Other Discoveries by Jyotiraditya Jadhav