Difference between revisions of "Lagrange's Mean Value Theorem"

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==Statement==
 
==Statement==
Let <math>f:([a,b]\rightarrow\mathbb{R}</math>
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Let <math>f:[a,b]\rightarrow\mathbb{R}</math>
  
 
Let <math>f</math> be continous on <math>[a,b]</math> and differentiable on <math>(a,b)</math>.
 
Let <math>f</math> be continous on <math>[a,b]</math> and differentiable on <math>(a,b)</math>.

Revision as of 10:25, 15 February 2008

Lagrange's mean value theorem or LMVT is considered one of the most important results in real analysis. An elegant proof of the Fundamental Theorem of Calculus can be given using LMVT.

Statement

Let $f:[a,b]\rightarrow\mathbb{R}$

Let $f$ be continous on $[a,b]$ and differentiable on $(a,b)$.

Then $\exists$ $c\in (a,b)$ such that $f'(c)=\frac{f(b)-f(a)}{b-a}$

Proof

We reduce the problem to the Rolle's theorem by using an 'auxillary function'.

Consider $g(x)=f(x)-\frac{f(b)-f(a)}{b-a}(x-a)$

note that $g(a)=g(b)=f(a)$

By Rolle's theorem, $\exists\; c\in (a,b)$ such that $g'(c)=0$

i.e. $f'(c)-\frac{f(b)-f(a)}{b-a}=0$

or $f'(c)=\frac{f(b)-f(a)}{b-a}$

QED

See Also