Difference between revisions of "Lcz's Mock AMC 10A Problems"

(Problem 3)
(Blanked the page)
(Tag: Blanking)
 
(47 intermediate revisions by 2 users not shown)
Line 1: Line 1:
==Instructions==
 
  
1. All rules of a regular AMC 10 apply.
 
 
2. Please submit your answers in a DM to me (Lcz).
 
 
3. Don't cheat.
 
 
Here's the problems!
 
 
==Problem 1==
 
 
Find the value of <math>2^{0+1+2}+2+0(1+(2))+20(12)</math>.
 
 
<math>\textbf{(A)}\ 8 \qquad\textbf{(B)}\ 248 \qquad\textbf{(C)}\ 250 \qquad\textbf{(D)}\ 252 \qquad\textbf{(E)}\ 254</math>
 
 
==Problem 2==
 
 
If <math>|x-2|=0</math>, and <math>|y-3|=1</math>, find the sum of all possible values of <math>|xy|</math>.
 
 
<math>\textbf{(A)}\ 0 \qquad\textbf{(B)}\ 4 \qquad\textbf{(C)}\ 8 \qquad\textbf{(D)}\ 12 \qquad\textbf{(E)}\ 16</math>
 
 
==Problem 3==
 
 
What is <math>1*2+2*3+3*4+4*5+5*6+6*7+7*8</math>?
 
 
<math>\textbf{(A)}\ 84 \qquad\textbf{(B)}\ 120 \qquad\textbf{(C)}\ 138 \qquad\textbf{(D)}\ 150 \qquad\textbf{(E)}\ 168</math>
 
 
==Problem 4==
 
 
Jack and Jill play a (bad) game on a number line which contains the integers. Jack starts at <math>-1</math>, and Jill starts at <math>18</math>. Every turn, the judge flip a standard six sided die. If the number rolled is a square number, Jack moves to the right <math>10</math> units. Otherwise, Jill moves to the left <math>5</math> units. Find the probability for which Jack and Jill pass each other for the first time in <math>3</math> moves.
 
 
<math>\textbf{(A)}\ 4/27 \qquad\textbf{(B)}\ 2/9 \qquad\textbf{(C)}\ 1/3 \qquad\textbf{(D)}\ 4/9 \qquad\textbf{(E)}\ 2/3</math>
 

Latest revision as of 16:13, 16 July 2020