# MIE 2015/Day 1/Problem 2

## Problem 2

The polynomial has real roots , and . Thus the value of the sum of is:

(a)

(b)

(c)

(d)

(e)

## Solution

By Girard's relations (also called Vieta's formulas or Newton's identities),

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Revision as of 14:25, 11 January 2018 by Alevini98 (talk | contribs) (Created page with "==Problem 2== The polynomial <math>x^3+ax^2+bx+c</math> has real roots <math>\alpha</math>, <math>-\alpha</math> and <math>\frac{1}{\alpha}</math>. Thus the value of the sum o...")

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The polynomial has real roots , and . Thus the value of the sum of is:

(a)

(b)

(c)

(d)

(e)

By Girard's relations (also called Vieta's formulas or Newton's identities),

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