# Difference between revisions of "Midpoint"

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The [[median of a triangle]] is defined as one of the three line segments connecting a midpoint to its opposite vertex. As for the case of Figure 2, the medians are <math>\overline{AE}</math>, <math>\overline{BF}</math>, and <math>\overline{CD}</math>, segments highlighted in red. | The [[median of a triangle]] is defined as one of the three line segments connecting a midpoint to its opposite vertex. As for the case of Figure 2, the medians are <math>\overline{AE}</math>, <math>\overline{BF}</math>, and <math>\overline{CD}</math>, segments highlighted in red. | ||

− | These three line segments are [[concurrent]] at point <math>G</math>, which is otherwise known as the [[centroid]]. This concurrence can be proven through many ways, one of which involves the most simple usage of [[Ceva's Theorem]] and the properties of a midpoint. | + | These three line segments are [[concurrent]] at point <math>G</math>, which is otherwise known as the [[centroid]]. This concurrence can be proven through many ways, one of which involves the most simple usage of [[Ceva's Theorem]] and the properties of a midpoint. A median is always within its triangle. |

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+ | The centroid is one of the points that trisect a median. For a median in any triangle, the ratio of the median's length from vertex to centroid and centroid to the base is always 2:1. | ||

== Cartesian Plane == | == Cartesian Plane == |

## Revision as of 23:41, 15 February 2021

## Contents

## Definition

The **midpoint** of a line segment is the point on the segment equidistant from both endpoints.

A midpoint bisects the line segment that the midpoint lies on. Because of this property, we say that for any line segment with midpoint , . Alternatively, any point on such that is the midpoint of the segment.

## Midpoints and Triangles

### Midsegments

As shown in Figure 2, is a triangle with , , midpoints on , , respectively. Connect , , (segments highlighted in green). They are midsegments to their corresponding sides. Using SAS Similarity Postulate, we can see that and likewise for and . Because of this, we know that Which is the Triangle Midsegment Theorem. Because we have a relationship between these segment lengths, with similar ratio 2:1. The area ratio is then 4:1; this tells us

### Medians

The median of a triangle is defined as one of the three line segments connecting a midpoint to its opposite vertex. As for the case of Figure 2, the medians are , , and , segments highlighted in red.

These three line segments are concurrent at point , which is otherwise known as the centroid. This concurrence can be proven through many ways, one of which involves the most simple usage of Ceva's Theorem and the properties of a midpoint. A median is always within its triangle.

The centroid is one of the points that trisect a median. For a median in any triangle, the ratio of the median's length from vertex to centroid and centroid to the base is always 2:1.

## Cartesian Plane

In the Cartesian Plane, the coordinates of the midpoint can be obtained when the two endpoints , of the line segment is known. Say that and . The Midpoint Formula states that the coordinates of can be calculated as:

## See Also

*This article is a stub. Help us out by expanding it.*