Difference between revisions of "Mock Geometry AIME 2011 Problems/Problem 6"

m (Solution)
m (Solution)
Line 6: Line 6:
 
<asy>
 
<asy>
 
unitsize(1cm);
 
unitsize(1cm);
 +
draw((0,3sqrt(3))--(3,0)--(12,0)--cycle);
 
draw((0, 18*sqrt(3))--(18, 0));
 
draw((0, 18*sqrt(3))--(18, 0));
 
draw((18, 0)--(36, 18*sqrt(3)));
 
draw((18, 0)--(36, 18*sqrt(3)));
 
</asy>
 
</asy>

Revision as of 19:03, 7 July 2019

Problem

Three points $A,B,C$ are chosen at random on a circle. The probability that there exists a point $P$ inside an equilateral triangle $A_1B_1C_1$ such that $PA_1=BC,PB_1=AC,PC_1=AB$ can be expressed in the form $\frac{m} {n},$ where $m,n$ are relatively prime positive integers. Find $m+n.$

Solution

The problem asks for the probability that point $P$ is inside an equilateral triangle $A_1B_1C_1$. Let $x$, $y$, and $z$ be the three distances from point $P$ to each of the vertices, with $x$ being the longest distance. Let's consider the case in which point $P$ is actually on the line: [asy] unitsize(1cm); draw((0,3sqrt(3))--(3,0)--(12,0)--cycle); draw((0, 18*sqrt(3))--(18, 0)); draw((18, 0)--(36, 18*sqrt(3))); [/asy]