Difference between revisions of "Perfect square"

 
m (Sum of squares formula)
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An [[integer]] <math>n</math> is said to be a '''perfect square''' if there is an integer <math>m</math> so that <math>m^2=n</math>. The first few perfect squares are 0, 1, 4, 9, 16, 25, 36.
 
An [[integer]] <math>n</math> is said to be a '''perfect square''' if there is an integer <math>m</math> so that <math>m^2=n</math>. The first few perfect squares are 0, 1, 4, 9, 16, 25, 36.
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The sum of the first <math>n</math> square numbers (not including 0) is <math>\frac{n(n+1)(2n+1)}{6}</math>
  
 
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Revision as of 08:30, 29 June 2006

An integer $n$ is said to be a perfect square if there is an integer $m$ so that $m^2=n$. The first few perfect squares are 0, 1, 4, 9, 16, 25, 36.

The sum of the first $n$ square numbers (not including 0) is $\frac{n(n+1)(2n+1)}{6}$

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