Difference between revisions of "Permutation"

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An important question is how many ways to pick an r-element subset of a set with n elements, where order matters.  To find how many ways we can do this, note that for the first of the r elements, we have n different objects we can choose from.  For the second element, there are (n-1) objects we can choose, (n-2) for the third, and so on.  In general, the number of ways to permute r objects from a set of n is given by
 
An important question is how many ways to pick an r-element subset of a set with n elements, where order matters.  To find how many ways we can do this, note that for the first of the r elements, we have n different objects we can choose from.  For the second element, there are (n-1) objects we can choose, (n-2) for the third, and so on.  In general, the number of ways to permute r objects from a set of n is given by
 
<math>P(n,r)=n(n-1)(n-2)\cdots(n-r+1)=\frac{n!}{(n-r)!}</math>.
 
<math>P(n,r)=n(n-1)(n-2)\cdots(n-r+1)=\frac{n!}{(n-r)!}</math>.
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== See also ==
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* [[Combinatorics]]
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Revision as of 19:33, 8 August 2006

A permutation of a set of r objects is any rearrangement of the r objects. There are $\displaystyle r!$ (the factorial of r) permutations of a set with r objects.

An important question is how many ways to pick an r-element subset of a set with n elements, where order matters. To find how many ways we can do this, note that for the first of the r elements, we have n different objects we can choose from. For the second element, there are (n-1) objects we can choose, (n-2) for the third, and so on. In general, the number of ways to permute r objects from a set of n is given by $P(n,r)=n(n-1)(n-2)\cdots(n-r+1)=\frac{n!}{(n-r)!}$.

See also

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