Difference between revisions of "Polynomial"

(A More Precise Definition)
(added Newton sums link)
Line 58: Line 58:
* [[Vieta's formulas]]
* [[Vieta's formulas]]
* [[Newton's identities]]
* [[Newton's identities]]
* [[Newton sums]]
==Other Resources==
==Other Resources==

Revision as of 12:05, 27 June 2006

A polynomial is a function in one or more variables that consists of a sum of variables raised to integral powers and multiplied by coefficients.

For example, these are polynomials:

  • $4x^2 + 6x - 9$
  • $x^3 + 3x^2y + 3xy^2 + y^3$
  • $5x^4 - 2x^2 + 9$

These aren't polynomials:

  • $\sin^2{x} + 5$
  • $\frac{4x+3}{2x-9}$

Introductory Topics

A More Precise Definition

A polynomial in one variable is a function $P(x) = a_nx^n + a_{n-1}x^{n-1} + \cdots + a_2x^2 + a_1x + a_0$. Here, $a_i$ is the $i$th coefficient and $a_n \neq 0$. The integer $n$ is called the degree of the polynomial. Often, the leading coefficient of a polynomial will be equal to 1. In this case, we say we have a monic polynomial.

Finding Roots of Polynomials

What is a root?

A root is a value for a variable that will make the polynomial equal zero. For an example, 2 is a root of $x^2 - 4$ because $2^2 - 4 = 0$. For some polynomials, you can easily set the polynomial equal to zero and solve the equations to find roots, but in some cases it is much more complicated.

The Fundamental Theorem of Algebra

The fundamental theorem of algebra states that any polynomial with complex coefficients can be written as

$P(x) = k(x-x_1)(x-x_2)\cdots(x-x_n)$ where $k$ is a constant, the $x_i$ are (not necessarily distinct) complex numbers and $n$ is the highest power of $x$ that $P(x)$ contains (also called the degree). It's very easy to find the roots of a polynomial in this form because the roots will be $x_1,x_2,...,x_n$. This also tells us that the degree of a given polynomial is at least as large as the number of distinct roots of that polynomial.


Different methods of factoring can help find roots of polynomials. Consider this polynomial:

$x^3 + 3x^2 - 4x - 12 = 0$

This polynomial easily factors to:

$(x+3)(x^2-4) = 0$

$(x+3)(x-2)(x+2) = 0$

Now, the roots of the polynomial are clearly -3, -2, and 2.

The Rational Root Theorem

We are often interested in finding the roots of polynomials with integral coefficients. Consider such a polynomial $P(x) = a_nx^n + a_{n-1}x^{n-1} + \cdots + a_2x^2 + a_1x + a_0$. It can be shown that if $P(x)$ has a rational root $\pm\frac{p}{q}$ and this fraction is fully reduced, then $p$ is a factor of $a_0$ and $q$ is a factor of $a_n$. This is convenient because it means we must check only a small number of cases to find all rational roots of many polynomials. It is also especially convenient when dealing with monic polynomials.

Descartes' Law of Signs

By the Fundamental Theorem of Algebra, the maximum number of distinct factors (not all necessarily real) of a polynomial of degree n is n. This tells us nothing about whether or not these roots are positive or negative. Decartes' Rule of Signs says that for a polynomial P(x), the number of positive roots to the equation is equal to the number of sign changes in the coefficients of the polynomial, or is less than that number by a multiple of 2. The number of negative roots to the equation is the number of sign changes in the coefficients of P(-x), or is less than that by a multiple of 2.

Binomial Theorem

Binomial theorem can be very useful for factoring and expanding polynomials.

Intermediate Topics

Olympiad Topics

Other Resources

An extensive coverage of this topic is given in A Few Elementary Properties of Polynomials by Adeel Khan.

See also

Invalid username
Login to AoPS