Difference between revisions of "Power of a Point Theorem/Introductory Problem 4"
(No difference)

Revision as of 09:27, 1 July 2006
Problem
(ARML) Chords and of a given circle are perpendicular to each other and intersect at a right angle. Given that and , find .
Solution
is a right triangle with hypotenuse 5 and leg 4. Thus, by the Pythagorean Theorem, (or by just knowing your Pythagorean Triples). Applying the Power of a Point Theorem gives or . Solving gives .
Back to the Power of a Point Theorem.