Difference between revisions of "Relatively prime"

m
m
 
Line 10: Line 10:
 
Two integers <math>a</math> and <math>b</math> are relatively prime if and only if there exist some <math>x,y\in \mathbb{Z}</math> such that <math>ax+by=1</math> (a special case of [[Bezout's Lemma]]). The [[Euclidean Algorithm]] can be used to compute the coefficients <math>x,y</math>.
 
Two integers <math>a</math> and <math>b</math> are relatively prime if and only if there exist some <math>x,y\in \mathbb{Z}</math> such that <math>ax+by=1</math> (a special case of [[Bezout's Lemma]]). The [[Euclidean Algorithm]] can be used to compute the coefficients <math>x,y</math>.
  
For two relatively prime numbers, their [[common multiples | Least Common Multiple]] is their product. This pops up in [[Chinese Remainder Theorem]].  
+
For two relatively prime numbers, their [[least common multiple]] is their product. This pops up in [[Chinese Remainder Theorem]].  
  
 
== See also ==
 
== See also ==

Latest revision as of 15:51, 25 February 2020

Two positive integers $m$ and $n$ are said to be relatively prime or coprime if they share no common divisors greater than 1. That is, their greatest common divisor is $\gcd(m, n) = 1$. Equivalently, $m$ and $n$ must have no prime divisors in common. The positive integers $m$ and $n$ are relatively prime if and only if $\frac{m}{n}$ is in lowest terms.

Number Theory

Relatively prime numbers show up frequently in number theory formulas and derivations:

Euler's totient function determines the number of positive integers less than any given positive integer that is relatively prime to that number.

Consecutive positive integers are always relatively prime, since, if a prime $p$ divides both $n$ and $n+1$, then it must divide their difference $(n+1)-n = 1$, which is impossible since $p > 1$.

Two integers $a$ and $b$ are relatively prime if and only if there exist some $x,y\in \mathbb{Z}$ such that $ax+by=1$ (a special case of Bezout's Lemma). The Euclidean Algorithm can be used to compute the coefficients $x,y$.

For two relatively prime numbers, their least common multiple is their product. This pops up in Chinese Remainder Theorem.

See also

This article is a stub. Help us out by expanding it.