# Search results

**Create the page "Scrabbler94" on this wiki!** See also the search results found.

- | scrabbler94 !scope="row" | scrabbler94's Mock AMC 1057 KB (6,904 words) - 16:41, 1 November 2021
- | scrabbler94 | scrabbler9426 KB (3,214 words) - 18:54, 13 July 2021
- ...the total is <math>96 + 16 = 112 \Longrightarrow \mathrm{(C)}</math>. (by scrabbler94)2 KB (315 words) - 01:10, 16 February 2021
- ...ability, the answer is <math>P = \boxed{\textbf{(A)} \frac{2}{5}}</math>. -scrabbler946 KB (861 words) - 22:37, 6 November 2021
- | scrabbler9418 KB (2,206 words) - 18:41, 24 December 2020
- (Solution by scrabbler94)5 KB (688 words) - 23:58, 27 November 2021
- -scrabbler944 KB (702 words) - 01:41, 21 February 2021
- -scrabbler944 KB (562 words) - 01:30, 16 February 2021
- -scrabbler942 KB (341 words) - 09:50, 30 March 2021
- ...ims, we see that this is possible if and only if <math>ab</math> is even. -scrabbler949 KB (1,610 words) - 18:34, 2 June 2020
- ...<math>MO = 8k + HM = \frac{196}{2} - 8 = \boxed{090}</math>. (Solution by scrabbler94)8 KB (1,298 words) - 17:08, 14 March 2021
- -scrabbler942 KB (272 words) - 01:29, 16 February 2021
- -scrabbler9415 KB (2,512 words) - 13:25, 4 November 2021
- ...h>) is the only candidate, giving <math>x=\boxed{\textbf{(B)} 11}</math>. -scrabbler943 KB (566 words) - 21:23, 9 July 2021
- (Credit to scrabbler94 for the idea) ~mathboy282, an expanded solution of Solution 5, credit to scrabbler94 for the idea.24 KB (3,745 words) - 18:04, 6 October 2021
- ~scrabbler9412 KB (2,025 words) - 21:15, 31 August 2021
- -scrabbler948 KB (1,371 words) - 00:25, 6 December 2021
- -scrabbler946 KB (1,041 words) - 20:50, 18 September 2021