# Search results

• | scrabbler94 !scope="row" | scrabbler94's Mock AMC 10
57 KB (6,904 words) - 16:41, 1 November 2021
• | scrabbler94 | scrabbler94
26 KB (3,214 words) - 18:54, 13 July 2021
• ...the total is $96 + 16 = 112 \Longrightarrow \mathrm{(C)}$. (by scrabbler94)
2 KB (315 words) - 01:10, 16 February 2021
• ...ability, the answer is $P = \boxed{\textbf{(A)} \frac{2}{5}}$. -scrabbler94
6 KB (861 words) - 22:37, 6 November 2021
• | scrabbler94
18 KB (2,206 words) - 18:41, 24 December 2020
• (Solution by scrabbler94)
5 KB (688 words) - 23:58, 27 November 2021
• -scrabbler94
4 KB (702 words) - 01:41, 21 February 2021
• -scrabbler94
4 KB (562 words) - 01:30, 16 February 2021
• -scrabbler94
2 KB (341 words) - 09:50, 30 March 2021
• ...ims, we see that this is possible if and only if $ab$ is even. -scrabbler94
9 KB (1,610 words) - 18:34, 2 June 2020
• ...$MO = 8k + HM = \frac{196}{2} - 8 = \boxed{090}$. (Solution by scrabbler94)
8 KB (1,298 words) - 17:08, 14 March 2021
• -scrabbler94
2 KB (272 words) - 01:29, 16 February 2021
• -scrabbler94
15 KB (2,512 words) - 13:25, 4 November 2021
• ...h>) is the only candidate, giving $x=\boxed{\textbf{(B)} 11}$. -scrabbler94
3 KB (566 words) - 21:23, 9 July 2021
• (Credit to scrabbler94 for the idea) ~mathboy282, an expanded solution of Solution 5, credit to scrabbler94 for the idea.
24 KB (3,745 words) - 18:04, 6 October 2021
• ~scrabbler94
12 KB (2,025 words) - 21:15, 31 August 2021
• -scrabbler94
8 KB (1,371 words) - 00:25, 6 December 2021
• -scrabbler94
6 KB (1,041 words) - 20:50, 18 September 2021