Difference between revisions of "Talk:Chinese Remainder Theorem/Introductory"

(More Info)
(misunderstanding the text)
Line 4: Line 4:
  
 
The writing style is fine, in my opinion.  However, I'm not sure that this covers the entire CRT; I'll try to add some more stuff.  There was a nice discussion of this in the SC forum. --[[User:Mysmartmouth|Sean]] 23:29, 22 June 2006 (EDT)
 
The writing style is fine, in my opinion.  However, I'm not sure that this covers the entire CRT; I'll try to add some more stuff.  There was a nice discussion of this in the SC forum. --[[User:Mysmartmouth|Sean]] 23:29, 22 June 2006 (EDT)
 +
 +
 +
== help ==
 +
 +
I didn't understand any of this part, the writing was unclear:
 +
"The standard solution is to notice that the number of fish plus 1 is divisible by each of the numbers 2, 3 and 5. Since they are pairwise relatively prime, by their product  and any number that, after adding 1 becomes divisible by 30 can be an answer to the problem (so he might catch 29, 59, 89, and so on fishes). That is fine, but the question remains: what would happen if instead of the numbers 2, 3, and 5 and remainders 1, 2, and 4, we had some other numbers and remainders? The most general question one may ask here is the following:"
 +
 +
I tried to sort it as well as I could.
 +
 +
Thanks,
 +
inscrutableroot

Revision as of 13:45, 23 June 2006

This is an experiment with writing style rather than anything else. I'd like to know whether such a style is acceptable, or you prefer something more formal (like Statement-Proof-Discussion format), or you would like to see some more "introductory" material. Please, share your opinions :).--Fedja 17:17, 21 June 2006 (EDT)

More Info

The writing style is fine, in my opinion. However, I'm not sure that this covers the entire CRT; I'll try to add some more stuff. There was a nice discussion of this in the SC forum. --Sean 23:29, 22 June 2006 (EDT)


help

I didn't understand any of this part, the writing was unclear: "The standard solution is to notice that the number of fish plus 1 is divisible by each of the numbers 2, 3 and 5. Since they are pairwise relatively prime, by their product and any number that, after adding 1 becomes divisible by 30 can be an answer to the problem (so he might catch 29, 59, 89, and so on fishes). That is fine, but the question remains: what would happen if instead of the numbers 2, 3, and 5 and remainders 1, 2, and 4, we had some other numbers and remainders? The most general question one may ask here is the following:"

I tried to sort it as well as I could.

Thanks,

inscrutableroot