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Talk:Geometric inequality

Revision as of 19:26, 24 June 2006 by Xantos C. Guin (talk | contribs)
(diff) ← Older revision | Latest revision (diff) | Newer revision → (diff)

Shouldn't the sign for the Isoperimetric Inequality be $\displaystyle \le$ not $\displaystyle <$ since a circle is a figure and $\displaystyle \frac{4 \pi (\pi r^{2})}{(2 \pi r)^{2}}=1$?

--Xantos C. Guin 19:26, 24 June 2006 (EDT)

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