Difference between revisions of "Talk:Newton's Sums"

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Isn't this called Newton's Sums instead of Newton sums?
 
Isn't this called Newton's Sums instead of Newton sums?
  
Most people I know call them Newton sums, but I believe the ``proper'' term is Newton-Gerard Identities. --[[User:ComplexZeta|ComplexZeta]] 22:41, 22 August 2006 (EDT)
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Most people I know call them Newton sums, but I believe the "proper" term is Newton-Gerard Identities. --[[User:ComplexZeta|ComplexZeta]] 22:41, 22 August 2006 (EDT)
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== Question ==
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<math>\displaystyle S_4 = r^4 + s^4 + t^4 = - 127 </math>. 
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How can the sum of squares equal a negative number (or does the polynomial have imaginary roots?).  --[[User:Mysmartmouth|Sean]] 17:22, 7 November 2006 (EST)
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Come now, you should be able to figure that one out for yourself (especially since 1 is a root of the polynomial).  --[[User:JBL|JBL]] 17:31, 7 November 2006 (EST)
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OK, wow, stupid question.  Whoooops! --[[User:Mysmartmouth|Sean]] 22:35, 7 November 2006 (EST)
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== Better Question ==
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Should we change the example to find <math>\displaystyle S_5</math> instead?  Reason being, this would show how to use the sums for higher powers, showing that you still only have 4 terms in your equation when you go for a sum that is greater than 4? (i.e. <math>\displaystyle S_4 + 3S_3 + 4S_2 - 8S_1 = 0</math> and then <math>\displaystyle S_5 + 3S_4 + 4S_3 - 8S_2 = 0</math>  (Hopefully you get my meaning) (this was something that confused me when I started learning Newton sums). --[[User:Mysmartmouth|Sean]] 22:40, 7 November 2006 (EST)

Latest revision as of 11:47, 1 September 2010

Isn't this called Newton's Sums instead of Newton sums?

Most people I know call them Newton sums, but I believe the "proper" term is Newton-Gerard Identities. --ComplexZeta 22:41, 22 August 2006 (EDT)

Question

$\displaystyle S_4 = r^4 + s^4 + t^4 = - 127$.

How can the sum of squares equal a negative number (or does the polynomial have imaginary roots?). --Sean 17:22, 7 November 2006 (EST)

Come now, you should be able to figure that one out for yourself (especially since 1 is a root of the polynomial). --JBL 17:31, 7 November 2006 (EST)

OK, wow, stupid question. Whoooops! --Sean 22:35, 7 November 2006 (EST)


Better Question

Should we change the example to find $\displaystyle S_5$ instead? Reason being, this would show how to use the sums for higher powers, showing that you still only have 4 terms in your equation when you go for a sum that is greater than 4? (i.e. $\displaystyle S_4 + 3S_3 + 4S_2 - 8S_1 = 0$ and then $\displaystyle S_5 + 3S_4 + 4S_3 - 8S_2 = 0$ (Hopefully you get my meaning) (this was something that confused me when I started learning Newton sums). --Sean 22:40, 7 November 2006 (EST)