Difference between revisions of "Triangle Inequality"

Revision as of 12:52, 25 June 2006

In a nondegenerate triangle $\displaystyle ABC$ :

$\displaystyle AB + BC > AC$

$\displaystyle BC + AC > AB$

$\displaystyle AC + AB > BC$

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Revision as of 10:34, 25 June 2006 (view source) Dschafer (talk \| contribs) (Added math tags) ← Older edit		Revision as of 12:52, 25 June 2006 (view source) ComplexZeta (talk \| contribs) m Newer edit →
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−	In a ~~non-trivial~~ triangle <math>\displaystyle ABC</math>:	+	In a nondegenerate triangle <math>\displaystyle ABC</math>:

	<math>\displaystyle AB + BC > AC</math>		<math>\displaystyle AB + BC > AC</math>