Difference between revisions of "Triangular number"

(Definition)
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==Definition==
 
==Definition==
The <math>n^{th}</math> triangular number is the sum of all natural numbers from one ton.
+
The <math>n^{th}</math> triangular number is the sum of all natural numbers from one to <math>n</math>.
 
That is, the <math>n^{th}</math> triangle number is  
 
That is, the <math>n^{th}</math> triangle number is  
 
<math>1 +2+3 + 4............. +(n-1)+(n)</math>.
 
<math>1 +2+3 + 4............. +(n-1)+(n)</math>.
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}
 
}
 
</asy>
 
</asy>
 +
 
==Formula==
 
==Formula==
  

Revision as of 22:41, 21 February 2019

The triangular numbers are the numbers $T_n$ which are the sum of the first $n$ natural numbers from $1$ to $n$.

Definition

The $n^{th}$ triangular number is the sum of all natural numbers from one to $n$. That is, the $n^{th}$ triangle number is $1 +2+3 + 4............. +(n-1)+(n)$.

For example, the first few triangular numbers can be calculated by adding 1, 1+2, 1+2+3, ... etc.

   }
   rowStart -= 0.5;
 }
 return 0;

}

for (int n=1; n<5; ++n) {

 real value= n*(n+1)/2;
 draw_triangle((value+5,n),n);
 label( (string) value, (value+5, -2));

} </asy>

Formula

Using the sum of an arithmetic series formula, a formula can be calculated for $T_n$:

$T_n =\sum_{k=1}^{n}k = 1 + 2 + \ldots + n = \frac{n(n+1)}2$


The formula for finding the $n^{th}$ triangular number can be written as $\dfrac{n(n+1)}{2}$.

It can also be expressed as the sum of the $n^{th}$ row in Pascal's Triangle and all the rows above it. Keep in mind that the triangle starts at Row 0.



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