Art of Problem Solving
AoPS Online
Math texts, online classes, and more
for students in grades 5-12.
Visit AoPS Online ‚
Books for Grades 5-12 Online Courses
Beast Academy
Engaging math books and online learning
for students ages 6-13.
Visit Beast Academy ‚
Books for Ages 6-13 Beast Academy Online
AoPS Academy
Small live classes for advanced math
and language arts learners in grades 2-12.
Visit AoPS Academy ‚
Find a Physical Campus Visit the Virtual Campus

Difference between revisions of "University of South Carolina High School Math Contest/1993 Exam/Problem 15"
Line 10: Line 10:
 
== Solution ==
 
== Solution ==
  
−
== See also ==
+
----
−
* [[University of South Carolina High School Math Contest/1993 Exam]]
+
 
 +
* [[University of South Carolina High School Math Contest/1993 Exam/Problem 14|Previous Problem]]
 +
* [[University of South Carolina High School Math Contest/1993 Exam/Problem 16|Next Problem]]
 +
* [[University of South Carolina High School Math Contest/1993 Exam|Back to Exam]]
  
 
[[Category:Intermediate Number Theory Problems]]
 
[[Category:Intermediate Number Theory Problems]]

Revision as of 12:17, 23 July 2006

Problem

If we express the sum

$\frac 1{3\cdot 5\cdot 7\cdot 11} + \frac 1{3\cdot 5\cdot 7\cdot 13} + \frac 1{3\cdot 5\cdot 11\cdot 13} + \frac 1{3\cdot 7\cdot 11\cdot 13} + \frac 1{5\cdot 7\cdot 11\cdot 13}$

as a rational number in reduced form, then the denominator will be

$\mathrm{(A) \ }15015 \qquad \mathrm{(B) \ }5005 \qquad \mathrm{(C) \ }455 \qquad \mathrm{(D) \ }385 \qquad \mathrm{(E) \ }91$

Solution

Retrieved from "https://artofproblemsolving.com/wiki/index.php?title=University_of_South_Carolina_High_School_Math_Contest/1993_Exam/Problem_15&oldid=8167"