Difference between revisions of "University of South Carolina High School Math Contest/1993 Exam/Problem 2"

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<math>3+x+3x=23 \Longrightarrow x=5</math>.
 
<math>3+x+3x=23 \Longrightarrow x=5</math>.
  
== See also ==
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* [[University of South Carolina High School Math Contest/1993 Exam]]
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* [[University of South Carolina High School Math Contest/1993 Exam/Problem 1|Previous Problem]]
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* [[University of South Carolina High School Math Contest/1993 Exam/Problem 3|Next Problem]]
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* [[University of South Carolina High School Math Contest/1993 Exam|Back to Exam]]
  
 
[[Category:Introductory Algebra Problems]]
 
[[Category:Introductory Algebra Problems]]

Revision as of 12:30, 23 July 2006

Problem

Suppose the operation $\star$ is defined by $a \star b = a+b+ab.$ If $3\star x = 23,$ then $x =$

$\mathrm{(A) \ } 2 \qquad \mathrm{(B) \ }3\qquad \mathrm{(C) \ }4 \qquad \mathrm{(D) \ }5 \qquad \mathrm{(E) \ }6$

Solution

$3+x+3x=23 \Longrightarrow x=5$.