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University of South Carolina High School Math Contest/1993 Exam/Problem 2

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Problem

Suppose the operation $\star$ is defined by $a \star b = a+b+ab.$ If $3\star x = 23,$ then $x =$

$\mathrm{(A) \ } 2 \qquad \mathrm{(B) \ }3\qquad \mathrm{(C) \ }4 \qquad \mathrm{(D) \ }5 \qquad \mathrm{(E) \ }6$

Solution

$3+x+3x=23 \Longrightarrow x=5$.

See also

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