Difference between revisions of "University of South Carolina High School Math Contest/1993 Exam/Problem 21"

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== Solution ==
 
== Solution ==
There are <math>{8\choose 2}-12=16</math> games.
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Revision as of 16:35, 18 August 2006

Problem

Suppose that each pair of eight tennis players either played exactly one game last week or did not play at all. Each player participated in all but 12 games. How many games were played among the eight players?

$\mathrm{(A) \ }10 \qquad \mathrm{(B) \ }12 \qquad \mathrm{(C) \ }14 \qquad \mathrm{(D) \ }16 \qquad \mathrm{(E) \ }18$

Solution

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