University of South Carolina High School Math Contest/1993 Exam/Problem 29

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Problem

If the sides of a triangle have lengths 2, 3, and 4, what is the radius of the circle circumscribing the triangle?

$\mathrm{(A) \ } 2 \qquad \mathrm{(B) \ } 8/\sqrt{15}  \qquad \mathrm{(C) \ } 5/2 \qquad \mathrm{(D) \ } \sqrt{6} \qquad \mathrm{(E) \ }  (\sqrt{6} + 1)/2$

Solution

Using Heron's Formula and $R=\frac{abc}{4A}$, the answer is $\frac{8}{\sqrt{15}}$.

See also