Difference between revisions of "User:I like pie"

m
Line 2: Line 2:
  
 
== For Future Use ==
 
== For Future Use ==
<math>\displaystyle\sum^{n}_{k=1}\left(\frac{1}{x}\right)^k=\frac{x^{n}-1}{x^{n}(x-1)}</math>
+
<math>\displaystyle\sum^{n}_{k=1}\frac{1}{x^{k}}=\frac{x^{n}-1}{x^{n}(x-1)}</math>
  
<math>\lim_{n\rightarrow\infty}\left(\displaystyle\sum^{n}_{k=1}\left(\frac{1}{x}\right)^k\right)=\frac{1}{x-1}</math>
+
<math>\lim_{n\rightarrow\infty}\left(\displaystyle\sum^{n}_{k=1}\frac{1}{x^{k}}\right)=\frac{1}{x-1}</math>
  
<math>\left\lceil\frac{x^{n}-1}{x^{n}}\right\rceil=\frac{1}{x-1}</math>
+
<math>\left\lceil\frac{x^{n}-1}{x^{n}(x-1)}\right\rceil=\frac{1}{x-1}</math>
  
<math>\frac{x^{n}-1}{x^{n}}<\frac{1}{x-1}</math>
+
<math>\frac{x^{n}-1}{x^{n}(x-1)}<\frac{1}{x-1}</math>

Revision as of 04:35, 4 November 2006

I am a user on AoPS, and go by the username i_like_pie. I enjoy playing soccer, programming, talking to my friends, fishing, reading, and many other things.

For Future Use

$\displaystyle\sum^{n}_{k=1}\frac{1}{x^{k}}=\frac{x^{n}-1}{x^{n}(x-1)}$

$\lim_{n\rightarrow\infty}\left(\displaystyle\sum^{n}_{k=1}\frac{1}{x^{k}}\right)=\frac{1}{x-1}$

$\left\lceil\frac{x^{n}-1}{x^{n}(x-1)}\right\rceil=\frac{1}{x-1}$

$\frac{x^{n}-1}{x^{n}(x-1)}<\frac{1}{x-1}$