Difference between revisions of "User:R31415"

Line 1: Line 1:
 
'''<math>e^i*e^\pi=-1</math>'''
 
'''<math>e^i*e^\pi=-1</math>'''
 +
Which means that i^i equals (e^i*e^\pi*e^1/2)^i= e^-\pi/2

Revision as of 21:04, 7 January 2011

$e^i*e^\pi=-1$ Which means that i^i equals (e^i*e^\pi*e^1/2)^i= e^-\pi/2