Difference between revisions of "User:R31415"

@@ Line 1: / Line 1: @@
-'''<math>e^ i\pi=-1</math>'''
-Which means that i^i equals <math>(e^i*e^\pi*e^ 1/2)^i= e^-\pi/2
-</math>(e^i*e^\pi*e^1/2)^i= e^-\pi/2$
-<dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/>

Page