User:R31415

Revision as of 21:05, 7 January 2011 by R31415 (talk | contribs)

$e^i*e^\pi=-1$ Which means that i^i equals $(e^i*e^\pi*e^1/2)^i= e^-\pi/2$(e^i*e^\pi*e^1/2)^i= e^-\pi/2 <dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/>