User:R31415

Revision as of 21:07, 7 January 2011 by R31415 (talk | contribs)

$e^ i\pi =-1$ Which means that i^i equals $(e^i*e^\pi*e^ 1/2)^i= e^-\pi/2$(e^i*e^\pi*e^1/2)^i= e^-\pi/2$ <dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/>
ah well... LaTeX is hard...