Difference between revisions of "User:Smarty101"

Revision as of 23:46, 14 February 2021

______________ 12/28/2020

His alcumus rating is now about 99.13

Here is one of the hardest problems: Let $p(x)$ be defined on $2 \le x \le 10$ such that $p(x) = \begin{cases} x + 1 &\quad \lfloor x \rfloor\text{ is prime} \\ p(y) + (x + 1 - \lfloor x \rfloor) &\quad \text{otherwise} \end{cases}$ where $y$ is the greatest prime factor of $\lfloor x\rfloor.$ Express the range of $p$ in interval notation.

When you find the answer click here and put the solution.

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-i'm a user on AoPS hi
+*i'm a user on AoPS hi
-Smarty101 likes to do [url=https://artofproblemsolving.com/alcumus/problem]Alcumus[/url] because he likes to practice math
+*He plays surviv.io
-He plays Surviv.io
+*he is good at math
-Subscribe to smarty101's youtube channel [[https://www.youtube.com/channel/UCCNW2O7R0YHFedWFHy8pnpg|here]] or else you'll have bad luck for a year.
+*As of 12/28/2020 7:36 PM his alcumus rating is 84.1
-go [[https://buddymeter.com/quiz.html?q=rcJkyb2|here]] to see how much u know about smarty101.
+*i like pizza and lasagna
-i like pizza and lasagna
+______________
+/28/2020
+His alcumus rating is now about 99.13
+*He has remembered all of the answers to Piecewise-Defined Functions
+*Here is one of the hardest problems: Let <math>p(x)</math> be defined on <math>2 \le x \le 10</math> such that<cmath>p(x) = \begin{cases} x + 1 &\quad \lfloor x \rfloor\text{ is prime} \\ p(y) + (x + 1 - \lfloor x \rfloor) &\quad \text{otherwise} \end{cases}</cmath>where <math>y</math> is the greatest prime factor of <math>\lfloor x\rfloor.</math> Express the range of <math>p</math> in interval notation.
+When you find the answer click [https://artofproblemsolving.com/wiki/index.php?title=User:Smarty101&action=edit here] and put the solution.
+*Take the buddymeter [https://buddymeter.com/quiz.html?q=rcJkyb2 here]
+==Subpages==
+[https://artofproblemsolving.com/wiki/index.php/User:Smarty101/Asymptote Asymptote]