User talk:Meljel

Revision as of 19:04, 16 January 2021 by Meljel (talk | contribs) (It's me meljel)

hi.

if ur from hysb then bye

hihiihi

\[a^2-b^2=(a+b)(a-b)\] \[(\cos \theta + i\sin \theta)^n = \cos n\theta + ii\sin n\theta\]

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