# Difference between revisions of "Wooga Looga Theorem"

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\tfrac16&0&\tfrac56 | \tfrac16&0&\tfrac56 | ||

\end{vmatrix}=\frac{7}{12}</cmath> so <math>[DEF]=42</math>. <math>\blacksquare</math> | \end{vmatrix}=\frac{7}{12}</cmath> so <math>[DEF]=42</math>. <math>\blacksquare</math> | ||

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+ | The Wooga Looga Theorem can be used to prove many problems and should be a part of any geometry textbook. | ||

+ | ~ilp2020 |

## Revision as of 11:50, 29 October 2020

The Wooga Looga Theorem states that the solution to this problem by franzliszt:

In points are on sides such that . Find the ratio of to .

is this solution by RedFireTruck:

WLOG let , , . Then and , , . Then . Therefore the answer is .

and that the solution to this problem by Matholic:

The figure below shows a triangle ABC which area is 72cm2. If AD: DB = BE: EC =CF: FA =1: 5, find the area of triangle DEF

is this solution by franzliszt:

We apply Barycentric Coordinates w.r.t. . Let . Then we find that . In the barycentric coordinate system, the area formula is where is a random triangle and is the reference triangle. Using this, we find that so .

The Wooga Looga Theorem can be used to prove many problems and should be a part of any geometry textbook.
~ilp2020