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k a April Highlights and 2025 AoPS Online Class Information
jlacosta   0
Apr 2, 2025
Spring is in full swing and summer is right around the corner, what are your plans? At AoPS Online our schedule has new classes starting now through July, so be sure to keep your skills sharp and be prepared for the Fall school year! Check out the schedule of upcoming classes below.

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[*]April 22nd (Webinar), 4:00pm PT/7:00pm ET, Competitive Programming at AoPS (USACO).[/list]
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0 replies
jlacosta
Apr 2, 2025
0 replies
k i A Letter to MSM
Arr0w   23
N Sep 19, 2022 by scannose
Greetings.

I have seen many posts talking about commonly asked questions, such as finding the value of $0^0$, $\frac{1}{0}$,$\frac{0}{0}$, $\frac{\infty}{\infty}$, why $0.999...=1$ or even expressions of those terms combined as if that would make them defined. I have made this post to answer these questions once and for all, and I politely ask everyone to link this post to threads that are talking about this issue.
[list]
[*]Firstly, the case of $0^0$. It is usually regarded that $0^0=1$, not because this works numerically but because it is convenient to define it this way. You will see the convenience of defining other undefined things later on in this post.

[*]What about $\frac{\infty}{\infty}$? The issue here is that $\infty$ isn't even rigorously defined in this expression. What exactly do we mean by $\infty$? Unless the example in question is put in context in a formal manner, then we say that $\frac{\infty}{\infty}$ is meaningless.

[*]What about $\frac{1}{0}$? Suppose that $x=\frac{1}{0}$. Then we would have $x\cdot 0=0=1$, absurd. A more rigorous treatment of the idea is that $\lim_{x\to0}\frac{1}{x}$ does not exist in the first place, although you will see why in a calculus course. So the point is that $\frac{1}{0}$ is undefined.

[*]What about if $0.99999...=1$? An article from brilliant has a good explanation. Alternatively, you can just use a geometric series. Notice that
\begin{align*}
\sum_{n=1}^{\infty} \frac{9}{10^n}&=9\sum_{n=1}^{\infty}\frac{1}{10^n}=9\sum_{n=1}^{\infty}\biggr(\frac{1}{10}\biggr)^n=9\biggr(\frac{\frac{1}{10}}{1-\frac{1}{10}}\biggr)=9\biggr(\frac{\frac{1}{10}}{\frac{9}{10}}\biggr)=9\biggr(\frac{1}{9}\biggr)=\boxed{1}
\end{align*}
[*]What about $\frac{0}{0}$? Usually this is considered to be an indeterminate form, but I would also wager that this is also undefined.
[/list]
Hopefully all of these issues and their corollaries are finally put to rest. Cheers.

2nd EDIT (6/14/22): Since I originally posted this, it has since blown up so I will try to add additional information per the request of users in the thread below.

INDETERMINATE VS UNDEFINED

What makes something indeterminate? As you can see above, there are many things that are indeterminate. While definitions might vary slightly, it is the consensus that the following definition holds: A mathematical expression is be said to be indeterminate if it is not definitively or precisely determined. So how does this make, say, something like $0/0$ indeterminate? In analysis (the theory behind calculus and beyond), limits involving an algebraic combination of functions in an independent variable may often be evaluated by replacing these functions by their limits. However, if the expression obtained after this substitution does not provide sufficient information to determine the original limit, then the expression is called an indeterminate form. For example, we could say that $0/0$ is an indeterminate form.

But we need to more specific, this is still ambiguous. An indeterminate form is a mathematical expression involving at most two of $0$, $1$ or $\infty$, obtained by applying the algebraic limit theorem (a theorem in analysis, look this up for details) in the process of attempting to determine a limit, which fails to restrict that limit to one specific value or infinity, and thus does not determine the limit being calculated. This is why it is called indeterminate. Some examples of indeterminate forms are
\[0/0, \infty/\infty, \infty-\infty, \infty \times 0\]etc etc. So what makes something undefined? In the broader scope, something being undefined refers to an expression which is not assigned an interpretation or a value. A function is said to be undefined for points outside its domain. For example, the function $f:\mathbb{R}^{+}\cup\{0\}\rightarrow\mathbb{R}$ given by the mapping $x\mapsto \sqrt{x}$ is undefined for $x<0$. On the other hand, $1/0$ is undefined because dividing by $0$ is not defined in arithmetic by definition. In other words, something is undefined when it is not defined in some mathematical context.

WHEN THE WATERS GET MUDDIED

So with this notion of indeterminate and undefined, things get convoluted. First of all, just because something is indeterminate does not mean it is not undefined. For example $0/0$ is considered both indeterminate and undefined (but in the context of a limit then it is considered in indeterminate form). Additionally, this notion of something being undefined also means that we can define it in some way. To rephrase, this means that technically, we can make something that is undefined to something that is defined as long as we define it. I'll show you what I mean.

One example of making something undefined into something defined is the extended real number line, which we define as
\[\overline{\mathbb{R}}=\mathbb{R}\cup \{-\infty,+\infty\}.\]So instead of treating infinity as an idea, we define infinity (positively and negatively, mind you) as actual numbers in the reals. The advantage of doing this is for two reasons. The first is because we can turn this thing into a totally ordered set. Specifically, we can let $-\infty\le a\le \infty$ for each $a\in\overline{\mathbb{R}}$ which means that via this order topology each subset has an infimum and supremum and $\overline{\mathbb{R}}$ is therefore compact. While this is nice from an analytic standpoint, extending the reals in this way can allow for interesting arithmetic! In $\overline{\mathbb{R}}$ it is perfectly OK to say that,
\begin{align*}
a + \infty = \infty + a & = \infty, & a & \neq -\infty \\
a - \infty = -\infty + a & = -\infty, & a & \neq \infty \\
a \cdot (\pm\infty) = \pm\infty \cdot a & = \pm\infty, & a & \in (0, +\infty] \\
a \cdot (\pm\infty) = \pm\infty \cdot a & = \mp\infty, & a & \in [-\infty, 0) \\
\frac{a}{\pm\infty} & = 0, & a & \in \mathbb{R} \\
\frac{\pm\infty}{a} & = \pm\infty, & a & \in (0, +\infty) \\
\frac{\pm\infty}{a} & = \mp\infty, & a & \in (-\infty, 0).
\end{align*}So addition, multiplication, and division are all defined nicely. However, notice that we have some indeterminate forms here which are also undefined,
\[\infty-\infty,\frac{\pm\infty}{\pm\infty},\frac{\pm\infty}{0},0\cdot \pm\infty.\]So while we define certain things, we also left others undefined/indeterminate in the process! However, in the context of measure theory it is common to define $\infty \times 0=0$ as greenturtle3141 noted below. I encourage to reread what he wrote, it's great stuff! As you may notice, though, dividing by $0$ is undefined still! Is there a place where it isn't? Kind of. To do this, we can extend the complex numbers! More formally, we can define this extension as
\[\mathbb{C}^*=\mathbb{C}\cup\{\tilde{\infty}\}\]which we call the Riemann Sphere (it actually forms a sphere, pretty cool right?). As a note, $\tilde{\infty}$ means complex infinity, since we are in the complex plane now. Here's the catch: division by $0$ is allowed here! In fact, we have
\[\frac{z}{0}=\tilde{\infty},\frac{z}{\tilde{\infty}}=0.\]where $\tilde{\infty}/\tilde{\infty}$ and $0/0$ are left undefined. We also have
\begin{align*}
z+\tilde{\infty}=\tilde{\infty}, \forall z\ne -\infty\\
z\times \tilde{\infty}=\tilde{\infty}, \forall z\ne 0
\end{align*}Furthermore, we actually have some nice properties with multiplication that we didn't have before. In $\mathbb{C}^*$ it holds that
\[\tilde{\infty}\times \tilde{\infty}=\tilde{\infty}\]but $\tilde{\infty}-\tilde{\infty}$ and $0\times \tilde{\infty}$ are left as undefined (unless there is an explicit need to change that somehow). One could define the projectively extended reals as we did with $\mathbb{C}^*$, by defining them as
\[{\widehat {\mathbb {R} }}=\mathbb {R} \cup \{\infty \}.\]They behave in a similar way to the Riemann Sphere, with division by $0$ also being allowed with the same indeterminate forms (in addition to some other ones).
23 replies
Arr0w
Feb 11, 2022
scannose
Sep 19, 2022
k i Marathon Threads
LauraZed   0
Jul 2, 2019
Due to excessive spam and inappropriate posts, we have locked the Prealgebra and Beginning Algebra threads.

We will either unlock these threads once we've cleaned them up or start new ones, but for now, do not start new marathon threads for these subjects. Any new marathon threads started while this announcement is up will be immediately deleted.
0 replies
LauraZed
Jul 2, 2019
0 replies
k i Basic Forum Rules and Info (Read before posting)
jellymoop   368
N May 16, 2018 by harry1234
f (Reminder: Do not post Alcumus or class homework questions on this forum. Instructions below.) f
Welcome to the Middle School Math Forum! Please take a moment to familiarize yourself with the rules.

Overview:
[list]
[*] When you're posting a new topic with a math problem, give the topic a detailed title that includes the subject of the problem (not just "easy problem" or "nice problem")
[*] Stay on topic and be courteous.
[*] Hide solutions!
[*] If you see an inappropriate post in this forum, simply report the post and a moderator will deal with it. Don't make your own post telling people they're not following the rules - that usually just makes the issue worse.
[*] When you post a question that you need help solving, post what you've attempted so far and not just the question. We are here to learn from each other, not to do your homework. :P
[*] Avoid making posts just to thank someone - you can use the upvote function instead
[*] Don't make a new reply just to repeat yourself or comment on the quality of others' posts; instead, post when you have a new insight or question. You can also edit your post if it's the most recent and you want to add more information.
[*] Avoid bumping old posts.
[*] Use GameBot to post alcumus questions.
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[*] Don't post other users' real names.
[*] Advertisements are not allowed. You can advertise your forum on your profile with a link, on your blog, and on user-created forums that permit forum advertisements.
[/list]

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Marathons!
Relays might be a better way to describe it, but these threads definitely go the distance! One person starts off by posting a problem, and the next person comes up with a solution and a new problem for another user to solve. Here's some of the frequently active marathons running in this forum:
[list][*]Algebra
[*]Prealgebra
[*]Proofs
[*]Factoring
[*]Geometry
[*]Counting & Probability
[*]Number Theory[/list]
Some of these haven't received attention in a while, but these are the main ones for their respective subjects. Rather than starting a new marathon, please give the existing ones a shot first.

You can also view marathons via the Marathon tag.

Think this list is incomplete or needs changes? Let the mods know and we'll take a look.
368 replies
jellymoop
May 8, 2015
harry1234
May 16, 2018
idk12345678 Math Contest
idk12345678   15
N 2 hours ago by martianrunner
Welcome to the 1st idk12345678 Math Contest.
You have 4 hours. You do not have to prove your answers.
Post \signup username to sign up. Post your answers in a hide tag and I will tell you your score.*


The contest is attached to the post

Clarifications

*I mightve done them wrong feel free to ask about an answer
15 replies
idk12345678
Yesterday at 2:34 PM
martianrunner
2 hours ago
Inequalities
sqing   0
3 hours ago
Let $ a,b,c,d\geq 0 ,a-b+d=21 $ and $ a+3b+4c=101 $. Prove that
$$ - \frac{1681}{3}\leq   ab - cd \leq 820$$$$ - \frac{16564}{9}\leq   ac -bd \leq 420$$$$ - \frac{10201}{48}\leq ad- bc \leq\frac{1681}{3}$$
0 replies
sqing
3 hours ago
0 replies
The minimum is tricky..
exoticc   5
N 5 hours ago by exoticc
Let \( a, b, c \geq 0 \) such that \( a + b + c = 3 \).
Find the minimum value of the following expression:

\[
P = \frac{a}{a^2 + b^3} + \frac{b}{b^2 + c^3} + \frac{c}{c^2 + a^3}
\]
5 replies
exoticc
Yesterday at 3:19 PM
exoticc
5 hours ago
law of log
Miranda2829   18
N 5 hours ago by RandomMathGuy500
5log (5²) + 8 ˡºᵍ₈4 =

is this answer 6?
18 replies
Miranda2829
Yesterday at 2:12 AM
RandomMathGuy500
5 hours ago
9 Have you taken the AMC 10 test before?
aadimathgenius9   107
N Apr 8, 2025 by Charizard_637
Have you taken the AMC 10 test before?
107 replies
aadimathgenius9
Jan 5, 2025
Charizard_637
Apr 8, 2025
What Are The Chances?
IbrahimNadeem   57
N Apr 8, 2025 by martianrunner
Hello, I'm curious to have honest advice on how far I can make it (by 11th-12th grade-ish);

If I have:

- Started AMC 8 study in 6th grade
- Started AMC 10 study in 7th grade
- Started practicing harder & went from 60 to around 100 on AMC 10 (on practice tests with official conditions)
- Started AMC 12 study in 8th grade
- Currently (fall of 8th grade) getting ~120 on AMC 10/12 & 7-10 while practicing AIME

At this rate, what are the chances of me making the USA(J)MO, for example, by ~11th grade?

Please be completely honest and don't hold back; This can be useful to see if I have the need to practice harder.
57 replies
IbrahimNadeem
Oct 31, 2021
martianrunner
Apr 8, 2025
amc10 chances?
aoh11   29
N Apr 5, 2025 by avyaank
if i got a 55.5 on amc10, what are my chances of making aime???
29 replies
aoh11
Apr 4, 2025
avyaank
Apr 5, 2025
Study tips/guides
DDCN_2011   2
N Mar 31, 2025 by ChickensEatGrass
Now that I'm done with Mathcounts, I want to get ready for the Amc 10. What is the best way to study other doing past test which I will do. I am starting the Aops volume 1 book and what else should I do to get into Aime?
2 replies
DDCN_2011
Mar 31, 2025
ChickensEatGrass
Mar 31, 2025
Amc10 prep question
Shadow6885   21
N Mar 23, 2025 by Shadow6885
My question is how much of the geo and IA textbooks is relevant to AMC 10?
21 replies
Shadow6885
Mar 17, 2025
Shadow6885
Mar 23, 2025
How important is math "intuition"
Dream9   16
N Mar 21, 2025 by Dream9
When I see problems now, they usually fall under 3 categories: easy, annoying, and cannot solve. Over time, more problems become easy, but I don't think I'm learning anything "new" so is higher level math like AMC 10 more about practice, so you know what to do when you see a problem? Of course, there's formulas for some problems but when reading a lot of solutions I didn't see many weird formulas being used and it was just the way to solve the problem was "odd".
16 replies
Dream9
Mar 19, 2025
Dream9
Mar 21, 2025
which course should I take
GlitchyBoy   15
N Mar 13, 2025 by parnikap
Hello AOPS community,
Should I take the Mathcounts/AMC8 Advanced course over the summer or the AMC 10 Intermediate course?
I'm a 7th grader who is aiming for DHR AMC 8 and AIME qual next year as well as nats mathcounts, but sillies a lot on some stuff.
Scores:
6th grade (2023-2024 year)
Mathcounts Chapter: 33 (21/12)
Mathcounts State: 19 (11/8)
AMC 8: 12 (idk how this happened)
didn't take AMC 10
7th grade (2024-2025 year, so right now)
Mathcounts Chapter: 28 (36 w/o sillies)
Mathcounts State: a score higher than my chapter score (I cant reveal exact until April)
AMC 8: 16 (the problems were randomized cuz online)
AMC 10A: 42 (guessed too much)
AMC 10B: 58.5 (:facepalm:)
In practice AMC 8's I consistently get around 20-22, and on mock AMC 10's I get around 9-12 problems correct (so about low-mid 80s). In mock state Mathcounts I get 26-28s. Several people in my state have said I have a free nats qual next year due to all the competition graduating, but I am aiming for 34+ on state next year for insurance and to see how far I can go. I also hope to get DHR AMC 8 in 2026 and AIME, but not sure whether to take the AMC 8 advanced or AMC 10 course. Should I retake AMC 8 advanced (i took it last summer) to get really good basics or take AMC 10 course, and will the AMC 10 course help me get DHR amc8?
Thank you for your help, its greatly appreciated
please respond I'm begging.
15 replies
GlitchyBoy
Mar 10, 2025
parnikap
Mar 13, 2025
AOPS course questions
GlitchyBoy   5
N Mar 13, 2025 by aoh11
Hi Aops,
I was wondering if an intro to algebra book from Aops is needed to take the intro to algebra b course
And would it be better to buy the book and just do it myself or take a course on AOPS for intro to algebra b?
I am aiming for aime and nats next year so what should I do?
is intro to algebra b, intro to c&p, and amc10 course enough or not?
and do intro to algebra b and intro to c&p help with mathcounts and AMC?
thank you!
5 replies
GlitchyBoy
Mar 12, 2025
aoh11
Mar 13, 2025
chances of getting into nats
superhuman233   2
N Mar 12, 2025 by sanaops9
I know these kinds of posts seem repetitive, but I am genuinely curious.


I am from NE, 34 in chapter (3rd place) and that chapter was probably either the most competitive or 2nd most competitive in the state (unless I am mistaken). I haven't taken the AMC 8, but I have mocked 91.5 on a mock AMC 10 from the 2024 AOPS AMC 10 Practice Competition. I mock around 25-30 on past MC states. I have been doing MC trainer and past tests to prepare. What are my chances of getting into nats? I know my scores are very low, but I have heard that my state NE is not very competitive.
2 replies
superhuman233
Mar 11, 2025
sanaops9
Mar 12, 2025
k chances for mathcounts nationals
JY2020   72
N Mar 12, 2025 by PenguFish
Hello everyone, I was a bit curious about my chances to get into mathcounts nationals this year. I'm an eighth grader living in Washington, I got a 14 on the amc8 and a 75/84 on the amc10, and a 36 on mathcounts chapter. Does anyone know what my chances are to getting into mathcounts nationals?
72 replies
JY2020
Mar 10, 2025
PenguFish
Mar 12, 2025
Eazy equation clap
giangtruong13   1
N Apr 6, 2025 by iniffur
Find all $x,y,z$ satisfy that: $$\frac{x}{y+z}=2x-1; \frac{y}{x+z}=3y-1;\frac{z}{x+y}=5z-1$$
1 reply
giangtruong13
Apr 5, 2025
iniffur
Apr 6, 2025
Eazy equation clap
G H J
G H BBookmark kLocked kLocked NReply
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giangtruong13
106 posts
#1 • 1 Y
Y by teomihai
Find all $x,y,z$ satisfy that: $$\frac{x}{y+z}=2x-1; \frac{y}{x+z}=3y-1;\frac{z}{x+y}=5z-1$$
This post has been edited 1 time. Last edited by giangtruong13, Apr 6, 2025, 7:28 AM
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iniffur
534 posts
#3 • 3 Y
Y by Sedro, alexheinis, giangtruong13
$$\frac{x}{y+z}=2x-1;~ \frac{y}{x+z}=3y-1;~\frac{z}{x+y}=5z-1$$
The previous hint related to a system wherein $~~5x-1~$ was the RHS of the third equation, now (surreptitiouly) amended to read

$~~5z-1~~$

Adding $~1~$ throughout

$\Longrightarrow \frac{S}{y+z}=2x; ~~\frac{S}{x+z}=3y;~~\frac{S}{x+y}=5z,~~$ wherein $~S=x+y+z~~~$

Eliminating $~S~~\Longrightarrow 2x(y+z)=3y(x+z)=5z(x+y)$

Expliciting $~y~$ from first + second eq: $\Longrightarrow y=\frac{2xz}{x+3z}$

Expliciting $~y~$ from first + third eq: $\Longrightarrow y=\frac{3xz}{2x-5z}$

$\Longrightarrow \frac{2xz}{x+3z}=\frac{3xz}{2x-5z}\Longrightarrow x=19z$

As regards the second equation in $~x,~z~$:

Expliciting $~y~$ from the unmodified first and third eq. yields:

$\frac{x}{2x-1}-z=\frac{z}{5z-1}-x\Longrightarrow (5z-1)(x+z-2xz)=(2x-1)(x+y-5xz)\Longrightarrow 10x^2z-2x^2-10xz^2+5z^2=0$

which combined with $~~ x=19z~~$ leads to

$z=\frac{239}{1140},~~ x=\frac{239}{60},~~ y= \frac{239}{660}$
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G
H
=
a