2001 AMC 12 Problems/Problem 14

Problem

Given the nine-sided regular polygon $A_1 A_2 A_3 A_4 A_5 A_6 A_7 A_8 A_9$, how many distinct equilateral triangles in the plane of the polygon have at least two vertices in the set $\{A_1,A_2,\dots,A_9\}$?

$\text{(A) }30 \qquad \text{(B) }36 \qquad \text{(C) }63 \qquad \text{(D) }66 \qquad \text{(E) }72$

Solution

Each of the $\binom{9}{2} = 36$ pairs of vertices determines $2$ equilateral triangles — one facing towards the center, and one outwards — for a total of $2 \cdot 36 = 72$ triangles. However, the $3$ triangles $A_1A_4A_7$, $A_2A_5A_8$, and $A_3A_6A_9$ are each counted $3$ times (once for each of the $\binom{3}{2} = 3$ possible pairs of vertices, all of which are vertices of the $9$-gon), whereas they should of course only be counted once, resulting in an overcount of $(3-1) \cdot 3 = 6$. Thus, there are $72-6 = \boxed{\text{(D) }66}$ distinct equilateral triangles.

Video Solution

https://youtu.be/gMWJisI9Ulk

See Also

2001 AMC 12 (ProblemsAnswer KeyResources)
Preceded by
Problem 13
Followed by
Problem 15
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All AMC 12 Problems and Solutions

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