2016 AMC 8 Problems/Problem 11

Problem

Determine how many two-digit numbers satisfy the following property: when the number is added to the number obtained by reversing its digits, the sum is $132.$

$\textbf{(A) }5\qquad\textbf{(B) }7\qquad\textbf{(C) }9\qquad\textbf{(D) }11\qquad \textbf{(E) }12$

Solution 1

We can see that the original number can be written as $10a+b$, where $a$ represents the tens digit and $b$ represents the units digit. When this number is added to the number obtained by reversing its digits, which is $10b+a$, the sum would be $11a+11b$. From this, we can construct the equation $11a+11b=132$, which simplifies to $a+b=12$. Since there are 7 pairs of such digits $a$ and $b$, $(3,9), (4,8), (5,7), (6,6), (7,5), (8,4), (9,3)$, the answer would be $\boxed{\textbf{(B) } 7}.$

~Aqf243

Video Solution (CREATIVE THINKING!!!)

https://youtu.be/G_0KQJhZKGY

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Video Solution

https://youtu.be/lbfbJea43ldk

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See Also

2016 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
Problem 10
Followed by
Problem 12
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All AJHSME/AMC 8 Problems and Solutions

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