Difference between revisions of "2016 AMC 8 Problems/Problem 11"
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| − | + | Determine how many two-digit numbers satisfy the following property: when the number is added to the number obtained by reversing its digits, the sum is <math>132.</math> | |
<math>\textbf{(A) }5\qquad\textbf{(B) }7\qquad\textbf{(C) }9\qquad\textbf{(D) }11\qquad \textbf{(E) }12</math> | <math>\textbf{(A) }5\qquad\textbf{(B) }7\qquad\textbf{(C) }9\qquad\textbf{(D) }11\qquad \textbf{(E) }12</math> | ||
Revision as of 11:32, 23 November 2016
Determine how many two-digit numbers satisfy the following property: when the number is added to the number obtained by reversing its digits, the sum is 
Solution
We can write the two digit number in the form of 
; reverse of is 
. The sum of those numbers is:
![\[(10a+b)+(10b+a)=132\]](http://latex.artofproblemsolving.com/6/f/d/6fd900ef889d9862c522232dbcf8838063afa806.png)
![\[11a+11b=132\]](http://latex.artofproblemsolving.com/8/7/3/8739636c62a0fe31852e4bc3a20648d3ab312286.png)
![\[a+b=12\]](http://latex.artofproblemsolving.com/6/0/5/6059e0bfc25919547d7e4be50406ff6eba53885d.png)
We can use brute force to find order pairs 
such that 
. Since 
and 
are both digits, both and have to be integers less than 
. Thus are ordered pairs are 
or 
ordered pairs.
| 2016 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 10 |
Followed by Problem 12 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
These problems are copyrighted © by the Mathematical Association of America, as part of the American Mathematics Competitions. 
