Difference between revisions of "2023 AMC 10A Problems/Problem 21"
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~Aopsthedude | ~Aopsthedude | ||
− | == Video Solution 1 by OmegaLearn == | + | ==Video Solution 1 by Math-X (First fully understand the problem!!!)== |
+ | https://youtu.be/GP-DYudh5qU?si=HDaV3kGwwywXP2J5&t=7475 | ||
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+ | ~Math-X | ||
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+ | == Video Solution 2 by OmegaLearn == | ||
https://youtu.be/aOL04sKGyfU | https://youtu.be/aOL04sKGyfU | ||
== Video Solution == | == Video Solution == | ||
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https://www.youtube.com/watch?v=HEqewKGKrFE | https://www.youtube.com/watch?v=HEqewKGKrFE | ||
− | ==Video Solution | + | ==Video Solution 3== |
https://youtu.be/Jan9feBsPEg | https://youtu.be/Jan9feBsPEg | ||
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~Steven Chen (Professor Chen Education Palace, www.professorchenedu.com) | ~Steven Chen (Professor Chen Education Palace, www.professorchenedu.com) | ||
− | ==Video Solution | + | ==Video Solution 4 by EpicBird08== |
https://www.youtube.com/watch?v=D4GWjJmpqEU&t=25s | https://www.youtube.com/watch?v=D4GWjJmpqEU&t=25s | ||
− | ==Video Solution | + | ==Video Solution 5 by MegaMath== |
https://www.youtube.com/watch?v=4Hwt3f1bi1c&t=1s | https://www.youtube.com/watch?v=4Hwt3f1bi1c&t=1s |
Revision as of 08:55, 5 September 2024
Contents
[hide]Problem
Let be the unique polynomial of minimal degree with the following properties:
has a leading coefficient
,
is a root of
,
is a root of
,
is a root of
, and
is a root of
.
The roots of are integers, with one exception. The root that is not an integer and can be written as
, where
and
are relatively prime integers. What is
?
Solution 1
From the problem statement, we know ,
and
. Therefore, we know that
,
, and
are roots. So, we can factor
as
, where
is the unknown root. Since
, we plug in
which gives
, therefore
. Therefore, our answer is
~aiden22gao
~cosinesine
~walmartbrian
~sravya_m18
~ESAOPS
~Andrew_Lu
Solution 2
We proceed similarly to solution one. We get that . Expanding, we get that
. We know that
, so the sum of the coefficients of the cubic expression is equal to one. Thus
. Solving for
, we get that
. Therefore, our answer is
~Aopsthedude
Video Solution 1 by Math-X (First fully understand the problem!!!)
https://youtu.be/GP-DYudh5qU?si=HDaV3kGwwywXP2J5&t=7475
~Math-X
Video Solution 2 by OmegaLearn
Video Solution
Video Solution by CosineMethod
https://www.youtube.com/watch?v=HEqewKGKrFE
Video Solution 3
~Steven Chen (Professor Chen Education Palace, www.professorchenedu.com)
Video Solution 4 by EpicBird08
https://www.youtube.com/watch?v=D4GWjJmpqEU&t=25s
Video Solution 5 by MegaMath
https://www.youtube.com/watch?v=4Hwt3f1bi1c&t=1s
See Also
2023 AMC 10A (Problems • Answer Key • Resources) | ||
Preceded by Problem 20 |
Followed by Problem 22 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |
These problems are copyrighted © by the Mathematical Association of America, as part of the American Mathematics Competitions.