2013 AMC 8 Problems/Problem 8
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Problem
A fair coin is tossed 3 times. What is the probability of at least two consecutive heads?
Solution
First, there are 
ways to flip the coins, in order.
The ways to get two consecutive heads are HHT and THH.
The way to get three consecutive heads is HHH.
Therefore 
of the possible flip sequences have at least two consecutive heads, and that is the probability.
See Also
| 2013 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 7 |
Followed by Problem 9 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
These problems are copyrighted © by the Mathematical Association of America, as part of the American Mathematics Competitions. 
