A Geometry Problem Revised

by luimichael, Nov 9, 2007, 1:17 PM

Given that ABC is an equilateral triangle of unknown side. P is a point inside triangle ABC with PA = 4, PB = 3 and PC = 5.
Find the size of the equilateral triangle.


Solution:
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Following the idea in the above solution, suppose the problem is defined in a more general setting as follows:
Given four points P, A,B and C in the same plane with PA = a, PB = b, PC = c and AB =BC =CA = x.
Determine the value of x in terms of a, b and c.


The solution is neat:
$ x = \sqrt {\frac {a^2 + b^2 + c^2 \pm 4\sqrt 3 \Delta}2}$ ,
where $ \Delta$ represents the area of triangle with sides a, b and c.
The plus or minus sign is determined by the following rule: Take a plus sign if the point P is inside triangle ABC and of course take a minus sign if P is outside triangle ABC.

Proof:

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Alternative proof:Click to reveal hidden text

Further questions:
1. What happens if P is outside triangle ABC ?
2. What is the formula for the general case?
That is to say, what is the expression for x if the lengths PA, PB and PC are given to be a, b and c respectively?
3. How comes the solution of this problem is apparently the same as that of the Fermat Point Problem

Answer:
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