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April Fools Geometry
awesomeming327.   6
N 42 minutes ago by GreekIdiot
Let $ABC$ be an acute triangle with $AB<AC$, and let $D$ be the projection from $A$ onto $BC$. Let $E$ be a point on the extension of $AD$ past $D$ such that $\angle BAC+\angle BEC=90^\circ$. Let $L$ be on the perpendicular bisector of $AE$ such that $L$ and $C$ are on the same side of $AE$ and
\[\frac12\angle ALE=1.4\angle ABE+3.4\angle ACE-558^\circ\]Let the reflection of $D$ across $AB$ and $AC$ be $W$ and $Y$, respectively. Let $X\in AW$ and $Z\in AY$ such that $\angle XBE=\angle ZCE=90^\circ$. Let $EX$ and $EZ$ intersect the circumcircles of $EBD$ and $ECD$ at $J$ and $K$, respectively. Let $LB$ and $LC$ intersect $WJ$ and $YK$ at $P$ and $Q$. Let $PQ$ intersect $BC$ at $F$. Prove that $FB/FC=DB/DC$.
6 replies
awesomeming327.
Apr 1, 2025
GreekIdiot
42 minutes ago
Functional equations
hanzo.ei   14
N 42 minutes ago by jasperE3
Source: Greekldiot
Find all $f: \mathbb R_+ \rightarrow \mathbb R_+$ such that $f(xf(y)+f(x))=yf(x+yf(x)) \: \forall \: x,y \in \mathbb R_+$
14 replies
hanzo.ei
Mar 29, 2025
jasperE3
42 minutes ago
Problem 1
SlovEcience   2
N an hour ago by Raven_of_the_old
Prove that
\[
C(p-1, k-1) \equiv (-1)^{k-1} \pmod{p}
\]for \( 1 \leq k \leq p-1 \), where \( C(n, m) \) is the binomial coefficient \( n \) choose \( m \).
2 replies
SlovEcience
2 hours ago
Raven_of_the_old
an hour ago
Conditional maximum
giangtruong13   1
N an hour ago by giangtruong13
Source: Specialized Math
Let $a,b$ satisfy that: $1 \leq a \leq2$ and $1 \leq b \leq 2$. Find the maximum: $$A=(a+b^2+\frac{4}{a^2}+\frac{2}{b})(b+a^2+\frac{4}{b^2}+\frac{2}{a})$$
1 reply
1 viewing
giangtruong13
Mar 22, 2025
giangtruong13
an hour ago
four variables inequality
JK1603JK   0
an hour ago
Source: unknown?
Prove that $$27(a^4+b^4+c^4+d^4)+148abcd\ge (a+b+c+d)^4,\ \ \forall a,b,c,d\ge 0.$$
0 replies
JK1603JK
an hour ago
0 replies
a hard geometry problen
Tuguldur   0
an hour ago
Let $ABCD$ be a convex quadrilateral. Suppose that the circles with diameters $AB$ and $CD$ intersect at points $X$ and $Y$. Let $P=AC\cap BD$ and $Q=AD\cap BC$. Prove that the points $P$, $Q$, $X$ and $Y$ are concyclic.
( $AB$ and $CD$ are not the diagnols)
0 replies
Tuguldur
an hour ago
0 replies
Problem 2
SlovEcience   0
an hour ago
Let \( a, n \) be positive integers and \( p \) be an odd prime such that:
\[
a^p \equiv 1 \pmod{p^n}.
\]Prove that:
\[
a \equiv 1 \pmod{p^{n-1}}.
\]
0 replies
SlovEcience
an hour ago
0 replies
Regarding Maaths olympiad prepration
omega2007   1
N 2 hours ago by GreekIdiot
<Hey Everyone'>
I'm 10 grader student and Im starting prepration for maths olympiad..>>> From scratch (not 2+2=4 )

Do you haves compilled resources of Handouts,
PDF,
Links,
List of books topic wise

which are shared on AOPS (and from your prespective) for maths olympiad and any useful thing, which will help me in boosting Maths olympiad prepration.
1 reply
omega2007
2 hours ago
GreekIdiot
2 hours ago
Induction
Mathlover_1   2
N 2 hours ago by GreekIdiot
Hello, can you share links of same interesting induction problems in algebra
2 replies
Mathlover_1
Mar 24, 2025
GreekIdiot
2 hours ago
n-gon function
ehsan2004   10
N 2 hours ago by Zany9998
Source: Romanian IMO Team Selection Test TST 1996, problem 1
Let $ f: \mathbb{R}^2 \rightarrow \mathbb{R} $ be a function such that for every regular $ n $-gon $ A_1A_2 \ldots A_n $ we have $ f(A_1)+f(A_2)+\cdots +f(A_n)=0 $. Prove that $ f(x)=0 $ for all reals $ x $.
10 replies
ehsan2004
Sep 13, 2005
Zany9998
2 hours ago
Congruency in sum of digits base q
buzzychaoz   3
N 2 hours ago by sttsmet
Source: China Team Selection Test 2016 Test 3 Day 2 Q4
Let $a,b,b',c,m,q$ be positive integers, where $m>1,q>1,|b-b'|\ge a$. It is given that there exist a positive integer $M$ such that
$$S_q(an+b)\equiv S_q(an+b')+c\pmod{m}$$
holds for all integers $n\ge M$. Prove that the above equation is true for all positive integers $n$. (Here $S_q(x)$ is the sum of digits of $x$ taken in base $q$).
3 replies
buzzychaoz
Mar 26, 2016
sttsmet
2 hours ago
Easy Geometry
bvdsf   2
N Apr 23, 2015 by jayme
Let $(C_1)$ be a circle with cwnter $O$. Let $AB$ be a chord of $(C_1)$, abd $C$ be a point on $AB$. The circumcircle of $OCA$, cuts $(C_1)$ at $D$. Prove that:

$BC=CD$
2 replies
bvdsf
Apr 22, 2015
jayme
Apr 23, 2015
Easy Geometry
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bvdsf
58 posts
#1 • 2 Y
Y by Adventure10, Mango247
Let $(C_1)$ be a circle with cwnter $O$. Let $AB$ be a chord of $(C_1)$, abd $C$ be a point on $AB$. The circumcircle of $OCA$, cuts $(C_1)$ at $D$. Prove that:

$BC=CD$
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andria
824 posts
#2 • 1 Y
Y by Adventure10
$ACOD$ is cyclic so $ODC=OAB=OBA$ also $ ODB=OBD$ so $ CDB=CBD $ DONE
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jayme
9775 posts
#3 • 1 Y
Y by Adventure10
Dear Mathlinkers,

1. E the second point of intersection of DO with (C1)
2. according to the Reim's theorem, OC// EB
3. according to Thales, EB perpendicular to BD
4. OC being the perpendicular bisector of BD, we are done...

Sincerely
Jean-Louis
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