USAMO 2011 Problem #5

by KingSmasher3, Apr 12, 2013, 11:39 PM

Let $P$ be a given point inside quadrilateral $ABCD$. Points $Q_1$ and $Q_2$ are located within $ABCD$ such that

$\begin{align*}\angle Q_1BC&=\angle ABP,&\angle Q_1CB&=\angle DCP,& \angle Q_2AD&=\angle BAP,& \angle Q_2DA&=\angle CDP.\end{align*}$

Prove that $\overline{Q_1Q_2}||\overline{AB}$ if and only if $\overline{Q_1Q_2}||\overline{CD}$.
_______

If $AB \| CD$ then obviously we are done. If not, then let $E$ be the intersection of $AB$ and $CD.$ Without loss of generality let $E$ be close to $B$ and $C$ than $A$ and $D.$ Now note that from the given angles, $P$ is the isogonal conjugate of $Q_1$ in $\triangle EBC$ and the isogonal conjugate of $Q_2$ in $\triangle EAB.$ This implies that both $Q_1$ and $Q_2$ lie on the reflection of $EP$ over the angle bisector of $\angle AEB.$ In other words, $E, Q_1, Q_2$ are collinear. However, this is a contradiction if either $\overline{Q_1Q_2}||\overline{AB}$ or $\overline{Q_1Q_2}||\overline{CD}.$

Therefore, $AB \| CD$ if either $\overline{Q_1Q_2}||\overline{AB}$ orif $\overline{Q_1Q_2}||\overline{CD},$ so we are done.

Main Point(s): When given the angle configuration as in this problem, isogonal conjugates should come to mind.
This post has been edited 1 time. Last edited by KingSmasher3, Apr 12, 2013, 11:39 PM

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