Intersecting Chords Theorem

by Puzzled417, Apr 2, 2016, 10:43 PM

Theorem. Let a chord intersect a circle $\omega$ at points $A,B$ and another chord intersect the circle at $C,D$ distinct from $A,B$. Denote by $\angle{X}$ the angle formed between the two chords that subtends $\overarc{AC}$ if they intersect. Then $\angle{X} = \frac{1}{2}(\overarc{AC}+\overarc{BD})$.

[asy]
import graph; usepackage("amsmath"); size(6.6cm); real lsf=0.5; pen dps=linewidth(0.7)+fontsize(10); defaultpen(dps); pen ds=black; real xmin=-4.98,xmax=6.62,ymin=-2.94,ymax=6.52; 
pair B=(0.96,0.14), A=(-2.8006041293639656,3.9917098915032883), D=(-2.234884510639143,0.10718758631715364), C=(1.9737458589080052,1.6565373027178305); 
draw(circle((-0.66,2.32),2.7160265094435285)); draw(A--B); draw(D--C); label("$\angle{X}$",(-0.08,1.66),SE*lsf); 
dot(B,linewidth(3.pt)+ds); label("$B$",(0.98,-0.2),NE*lsf); dot(A,linewidth(3.pt)+ds); label("$A$",(-3.,4.1),NE*lsf); dot(D,linewidth(3.pt)+ds); label("$D$",(-2.56,-0.2),NE*lsf); dot(C,linewidth(3.pt)+ds); label("$C$",(2.1,1.64),NE*lsf); 
clip((xmin,ymin)--(xmin,ymax)--(xmax,ymax)--(xmax,ymin)--cycle); 
[/asy]

Proof
Remark
This post has been edited 1 time. Last edited by Puzzled417, Apr 12, 2016, 3:33 PM

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