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first shouts in 2025!
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NicoN9, Apr 25, 2025, 12:56 PM
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dang 2 year bump (can the person who next visits PM me? I want to see when the next person visits)
by
roribaki, Jan 6, 2024, 9:18 PM
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wholsome
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samrocksnature, Aug 24, 2021, 4:16 PM
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wholesome
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centslordm, Jul 2, 2021, 2:08 PM
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cool blog
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lneis1, Feb 20, 2021, 6:11 AM
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Hello.Very nice blog!
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Functional_equation, Aug 29, 2020, 2:20 PM
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Great blog!
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freeman66, Jun 3, 2020, 1:25 AM
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Hello. Nice blog!
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mathboy282, Apr 10, 2020, 1:39 AM
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Masterpiece
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Kamran011, Mar 18, 2020, 6:35 PM
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Hello! Why am I looking through random blogs?
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bingo2016, Nov 21, 2019, 2:40 AM
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I am late to find this wonderful gem
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RAMUGAUSS, Nov 13, 2019, 7:32 AM
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I WILL NECROPOST
I WILL NECROPOST
I WILL NECROPOST
I WILL NECROPOST
I WILL NECROPOST
I WILL NECROPOST
I WILL NECROPOST
I WILL NECROPOST
I WILL NECROPOST
I WILL NECROPOST
I WILL NECROPOST
I WILL NECROPOST
I WILL NECROPOST
I WILL NECROPOST
I WILL NECROPOST
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Davis1234567890, Sep 15, 2019, 2:21 AM
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This is a nice blog and it is very useful!
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arandomperson123, Jun 7, 2016, 2:32 AM
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bump,,,,
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ythomashu, Jan 15, 2016, 12:51 AM
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Incredible
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DanielL2000, Jul 24, 2014, 9:34 PM
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Are you still in school?
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harekrishna, Feb 8, 2010, 6:58 PM
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ANNOUNCEMENT
My Regional Tests are tomorrow (29 th Nov.), and after that I have my school exams, so it seems as if this blog will not be updated for around a week. Sorry for the inconvenience.
Sincerely,
Potla
(creator and owner of this blog 
)
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Potla, Nov 27, 2009, 7:23 PM
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Nice. Keep working
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mathson, Oct 6, 2009, 11:29 AM
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Not at all.
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Potla, Sep 4, 2009, 10:35 AM
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Wow! You are very smart.
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Maybach, Sep 1, 2009, 12:56 AM
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good going
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turikachi, May 16, 2009, 3:40 AM
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Because of my exams..... 
I must do some work now.
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Potla, Apr 9, 2009, 9:51 AM
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well, why no activity here?
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Ramchandran, Apr 6, 2009, 1:46 PM
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Thanks for all of yours' kind( )coordination, but I cannot update this bulky(
: ) blog till my exams are over, so I want the contrib to continue their job (I am making peine a contrib too)....... 
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Potla, Mar 3, 2009, 12:56 PM
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Really nice solutions.......
However Iliked ochas and murgis problem more because of its simplicity.
however mathias DK sol is just awe strucking
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UKO, Feb 14, 2009, 4:47 AM
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@ mathias DK really your proof is beautifull
I didnot wanted to be rude .never mind. 
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murgi, Feb 14, 2009, 4:12 AM
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@murgi: I just wanted to provide a more beatiful proof.
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Mathias_DK, Feb 13, 2009, 11:08 PM
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I couldnot understand why such acomplicated proof is necessary?
when there exits such a simple proof.
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murgi, Feb 13, 2009, 5:11 PM
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From now on, this is the place of problem solvers.
Each problem for the day will bring 10 points to the first one to give a solution. Better solutions with ideas other than the ones before will also bring 10 points to the user. Meanwhile, incorrect problems will lose 5 points, so be careful while answering.
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Potla, Feb 13, 2009, 10:28 AM
by Rijul saini, Mar 18, 2011, 5:40 AM 
such that![\[f\left(f(x)+y\right)=2x+f\left(f(y)-x\right)\]](//latex.artofproblemsolving.com/e/b/4/eb4e0d6580d9d3d6a627e39837edb3d1943d4596.png)
such that![\[f\left(f(x)+y\right)=2x+f\left(f(y)-x\right)\]](http://latex.artofproblemsolving.com/e/b/4/eb4e0d6580d9d3d6a627e39837edb3d1943d4596.png)
denote the assertion 
.![\[P(0,x) \implies f(x+f(0)) = f(f(x))\]](http://latex.artofproblemsolving.com/6/8/9/689fa05d6b06f83ecc67a096399fa8f6c4a9c288.png)
![\[P(f(y),y) \implies f(f(f(y)) + y ) = 2f(y)+f(0) \implies f(f(y+f(0))+y) = 2f(y) + f(0)\]](http://latex.artofproblemsolving.com/3/2/5/3259044d54ae98f992aa852135aa637f5bc73f7d.png)
here, implies 
.![\[P(-\frac x2, -f(-\frac x2) - f(0)) \implies x = f(f(-f(-\frac x2) - f(0)) + \frac x2)\]](http://latex.artofproblemsolving.com/5/c/3/5c3ff8aa7fe4587c69b6981c63646b8eaecf73b9.png)
is onto i.e. covers all values of 
.
,
as 
.
for 
,![\[g(g(x+c) + y + c) = 2x + g(g(y+c) - x +c)\]](http://latex.artofproblemsolving.com/3/c/0/3c0630d9ad9a8502ea0b08d97b84c5fbf3c0fe24.png)
.![\[Q(-c,x-c) \implies g(x) = -2c + g(g(x) + 2c) \implies g(g(x) + 2c) = g(x) + 2c\]](http://latex.artofproblemsolving.com/f/d/d/fdd556975dbe1c53c807bda6eba419f927729da8.png)
covers all values of 
also covers all values of 
for every 
for every 
and this is indeed a solution.
March 2012
December 2011